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Andreas93 [3]
3 years ago
12

A 56.8g sample of aluminum is heated from 79.5°C to 143.7°C. The specific heat capacity of aluminum is 0.900 J/(g*K). Calculate

the heat absorbed.
A) 3280 J
B) 4440 J
C) 6220 J
D) 11400 J
Chemistry
1 answer:
Mashutka [201]3 years ago
4 0

Answer:

I think the answer is A.

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Design and implement a program (name it SumValue) that reads three integers (say X, Y, and Z) and prints out their values on sep
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Answer:

class sum (

public static void sumofvalue (int m, int n, int p)

{

System.out.println(m);

System.out.println(n);

System.out.println(p);

int SumValue=m+n+p;

System.out.println("Average="+Sumvalue/3);

}

)

Public class XYZ

(

public static void main(String [] args)

{

sum ob=new sum();

int X=3;

int X=4;

int X=5;

ob.sumofvalue(X,Y,Z);

int X=7;

int X=8;

int X=10;

ob.sumofvalue(X,Y,Z);

}

)

Explanation:

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The processing of the program is given below in detail

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