The graph shows the production of Fe, from the graph that it increases rapidly and then slowly increases.<span>The answer is a! (:
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Answer:
To have the same kinetic energy the speed of the marble must be 9 times the speed of rock.
Explanation:
The general formula of kinetic energy is given as follows:

where,
K.E = Kinetic Energy
m = mass of the object
v = speed of the object
So, for the marble and rock to have same kinetic energy, we can write:

<u>Hence, to have the same kinetic energy the speed of the marble must be 9 times the speed of rock.</u>
Answer:
The correct option is;
B. Object X travels at -2 m/s and object Y travels at 4 m/s after the spring is no longer compressed
Explanation:
The given parameters are;
The mass of object Y = M
The mass of object X = 2·M
The initial velocity of object X and object Y = 0 m/s
Let A represent the velocity of object X after the spring is released and B represent the velocity of object Y after the spring is released, therefore, by the principle of the conservation of linear momentum, we have;
(M + 2·M) × 0 = M × B + 2·M × A
∴ (M + 2·M) × 0 = 0 = M × B + 2·M × A
M × B = -2·M × A
∴ B = -2·A
Therefore, the velocity of the object Y = -2 × The velocity of the object X
Whereby the velocity of the object X = -2, The velocity of the object Y = -2 × -2 = 4
Which gives, object X travels at -2 m/s and object Y travels at 4 m/s after the spring is no longer compressed.
Answer:
A. Mass is a measure of the amount of matter in an object, while weight is a measure of the force of gravity on the object.
Explanation:
Mass is also a scalar quantity associated with the amount of atoms and/or molecules that constitutes the object. While weight is a force due to the action of gravity (either on our planet or any other one) and therefore a vector quantity that we routinely use as scalar due to the fact that it is always pointing down (towards the center of the Earth) so we ignore a bit the direction associated with it.
Answer:
the types of force shown in the picture is
<u>balanced</u><u> </u><u>force</u><u>.</u>