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S_A_V [24]
3 years ago
14

Classify the following bonds as ionic, covalent, or neither (O, atomic number 8; F, atomic number 9; Na, atomic number 11; Cl, a

tomic number 17; U, atomic number 92). O with F Ca with Cl Na with Na
Chemistry
1 answer:
mylen [45]3 years ago
6 0

Answer:

1. Oxygen Fluoride (O with F): covalent

2. Calcium Chloride (Ca with Cl): ionic

3. Sodium with Sodium (Na with Na): neither

Explanation:

1. Oxygen Fluoride (OF2)

Oxygen with Fluorine is covalent because both of these elements are <em>nonmetals</em>. Bonds that contain only nonmetals are covalent.

2. Calcium Chloride (CaCl2)

Calcium with Chlorine is ionic because there is one <em>metal </em>and one <em>nonmetal. </em>Bonds that contain one metal and one nonmetal are ionic.

3. Sodium with Sodium

Since this is not Sodium bonding with another element, it is neither ionic or covalent.

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Complete and balance the following acid-base equations:
Alchen [17]

Answer:

a) HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O

b) H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)

c) Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O

Explanation:

a)

when HClO_4 is added to LiOH, lithium chlorate and water is formed.

HClO_4 (aq) + LiOH \rightarrow LiClO_4 + H_2O

Balancing of above reaction,

It can be seen that all the atoms in both the sides are balanced. so it is a balanced reaction.

(b) When aqueous H_2SO_4 is added to NaOH, Na_2SO_4 and H_2O is formed. It is a neutrilization reaction.

H_2SO_4(aq) + NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)

Balancing of above reaction,

First balance all the atoms except O and H

S atom is already balanced in either side

No. of Na atom in left hand side = 1

No. of Na atom in right hand side = 2

So multiply NaOH by 2, now the reaction becomes:

H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + H_2O (l)

No. of O atoms in left hand side = 6

No. of O atoms in right hand side = 5

So multiply H2O by 2, now the reaction becomes:

H_2SO_4(aq) + 2NaOH(aq) \rightarrow Na_2SO_4 (aq) + 2H_2O (l)

Now, it can been seen that all the atoms are balanced.

c) When Ba(OH)2 reacts with HF, baroum fluoride and water is formed.

Ba(OH)2 + HF\rightarrow BaF_2 + H_2O

Balancing of above reaction,

Barium atoms are already balanced on either side.

No. of F atoms on left hand side = 1

No. of F atoms on right hand side = 2

So, multiply HF by 2, now reaction becomes

Ba(OH)2 + 2HF\rightarrow BaF_2 + H_2O

In order to balance H and O on either side, multiply H2O by 2.

Ba(OH)2 + 2HF\rightarrow BaF_2 + 2H_2O

7 0
3 years ago
Why is our mindset more important when you try to learn remotely than when you are learning face to face?
Marrrta [24]

Answer:

It is more important because of the freedom.

Explanation:

While at home you can do your work of course... but you could lay down, take a nap. You could get on the game, play around. You could draw, and fiddle and dance and do WHATEVER you want with no teacher to stop you so you have to be your own motivation. You have to be your own teacher or its VERY easy to fail.

5 0
3 years ago
How many grams of solid NaOH are required to prepare a 400ml of a 5N solution? show your work!
Nuetrik [128]

<u>Answer:</u> The mass of solid NaOH required is 80 g

<u>Explanation:</u>

Equivalent weight is calculated by dividing the molecular weight by n factor. The equation used is:

\text{Equivalent weight}=\frac{\text{Molecular weight}}{n}

where,

n = acidity for bases = 1 (For NaOH)

Molar mass of NaOH = 40 g/mol

Putting values in above equation, we get:

\text{Equivalent weight}=\frac{40g/mol}{1eq/mol}=40g/eq

Normality is defined as the umber of gram equivalents dissolved per liter of the solution.

Mathematically,

\text{Normality of solution}=\frac{\text{Number of gram equivalents} \times 1000}{\text{Volume of solution (in mL)}}

Or,

\text{Normality of solution}=\frac{\text{Given mass}\times 1000}{\text{Equivalent mass}\times \text{Volume of solution (in mL)}}         ......(1)

We are given:

Given mass of NaOH = ?

Equivalent mass of NaOH = 40 g/eq

Volume of solution = 400 mL

Normality of solution = 5 eq/L

Putting values in equation 1, we get:

5eq/L=\frac{\text{Mass of NaOH}\times 1000}{40g/eq\times 400mL}\\\\\text{Mass of NaOH}=80g

Hence, the mass of solid NaOH required is 80 g

4 0
4 years ago
A metallic substance has a volume of 10.5 cm' and a mass of 81.9 grams.What is the density of this substance
nalin [4]

Answer:

7.8 grams per cm

Explanation:

to get density you need the mass and volume then you divide them so

81.9 grams/10.5 cm gives 7.8g/cm

4 0
3 years ago
A compound needed for photosynthesis​
Pavel [41]

Answer:

Carbon dioxide as well as water are needed for photosynthesis.

Explanation:

8 0
3 years ago
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