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adoni [48]
3 years ago
13

Select the correct text in the passage. Read the profile of four engineers at different stages of their careers. Which one is an

engineer-in-training? Rowena is in her third year of a four-year BE degree in civil engineering.
Stephanie has completed her BSET In aeronautical engineering and has passed the Fundamentals of Engineering written exam.

Doug has completed an AAS In electrical engineering and is working in a firm under the guidance of a professional engineer.

Clifford has completed a Be in agricultural engineering and has four years of work experience.​
Engineering
1 answer:
Mumz [18]3 years ago
3 0

Answer:

Doug has completed an AAS In electrical engineering and is working in a firm under the guidance of a professional engineer.

Explanation:

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At a certain location, wind is blowing steadily at 7 m/s. Determine the mechanical energy of air per unit mass and the power gen
Kaylis [27]

Answer:

Explanation:

From the information given;

The velocity of the wind blow V = 7 m/s

The diameter of the blades  (d) = 80 m

Percentage of the overall efficiency \eta_{overall} = 30\%

The density of air \rho = 1.25 kg/km^3

Then, we can use the concept of the kinetic energy of the wind blowing to estimate the mechanic energy of air per unit mass by using the formula:

e_{mechanic} = \dfrac{mV^2}{2}

here;

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= 43982.29 kg/s

∴

W = e_{mechanic} = \dfrac{mV^2}{2}

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The actual electric power is:

W_{electric} = \eta_{overall} \times W

W_{electric} = 0.3 \times 1077.566

\mathbf{W_{electric} =323.26 \ kW}

8 0
2 years ago
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erma4kov [3.2K]

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Explanation:

3 0
2 years ago
A 1 m wide continuous footing is designed to support an axial column load of 250 kN per meter of wall length. The footing is pla
creativ13 [48]

Answer:

correct option is (A) 0.5

Explanation:

given data

axial column load = 250 kN per meter

footing placed =  0.5 m

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solution

we know angle of internal friction is 5° that is near to 0°

so it means the soil is almost cohesive soil.

and for  a pure cohesive soil

N_{\gamma } = 0

and we know formula for N_{\gamma } is

N_{\gamma } = (Nq - 1 ) × tan(Ф)   ..................1

so here Ф is very less  N_{\gamma } should be nearest to zero

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so correct option is (A) 0.5

7 0
3 years ago
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Roman55 [17]

Answer:

i dont understand

Explanation:

4 0
3 years ago
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