Question

The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 mm

Answer 1

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x $10^{-12}$ m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x $10^{-12}$

                                               = 260 x $10^{-12}$ m

Given a distance of 1.30 mm = 1.30 x $10^{-3}$ m,

The number of vanadium atoms required to span the distance = $\frac{1.3*10^{-3} }{260*10^{-12} }$

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.