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slega [8]
4 years ago
7

The graph above shows the progress of a chemical reaction. Based on the graph, which of the following is true?

Chemistry
2 answers:
Margarita [4]4 years ago
7 0

Answer: b. Reaction A is not enzyme-catalyzed, while reaction B is enzyme-catalyzed

Explanation:

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.  It is the difference between the energy of activated complex and energy of reactants.

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

Helen [10]4 years ago
6 0
I believe the answers b
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What is mass????????????????????
lbvjy [14]

Answer:

Do you need the definition or the equation to find it?

Explanation:

Equation:

Mass=volume x density

4 0
3 years ago
Select the correct answer.
rewona [7]
We can use the formula P=IV to calculate the current, where “P” is power (measured in watts), “I” is current (measured in Amps), and “V” is voltage. Simply plug and solve:

P = IV
(3.5 Watts) = I(120 volts)
I = 0.0292 Amps

The current flowing through the bulb is approximately 0.0292 Amps.

Hope this helps!
5 0
3 years ago
A drop of water weighing 0.48 g is vaporized at 100 ?c and condenses on the surface of a 55-g block of aluminum that is initiall
irakobra [83]
<h3><u>Answer;</u></h3>

<em>-49 °C</em>

<h3><u>Explanation and solution;</u></h3>
  • Considering the fact that, the specific heat capacity of aluminum is 0.903 J/g x C, and the heat of vaporization of water at 25 C is 44.0 KJ/mol.  

Moles water = 0.48 g / 18.02 g/mol

                      =0.0266  moles

<em>Heat lost by water</em> = 0.0266 mol x 44.0 kJ/mol

                                 =1.17 kJ => 1170 J  

<em>But heat lost =heat gained</em>

<em>Therefore;</em> Heat gained by aluminium = 1170 J  

        1170 = 55 x 0.903 ( T - 25) = 49.7 T - 1242  

                   1170 + 1242 = 49.7 T  

            T = 48.5 °C ( 49 °C <em>at two significant figures)</em>

<em>Hence</em>, final temperature = 49 °C

4 0
3 years ago
Read 2 more answers
Cho m gam FeO tác dụng hết với dung dịch H2SO4, thu được 200 ml dung dịch FeSO4 1M. Giá trị của m là
BaLLatris [955]

<u>Answer:</u> The mass of FeO required is 14.37 g

<u>Explanation:</u>

Molarity is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles}}{\text{Volume}} ......(1)

We are given:  

Molarity of iron (II) sulfate = 1 M

Volume of solution = 200 mL = 0.200 L (Conversion factor: 1 L = 1000 mL)

Putting values in equation 1, we get:

\text{Moles of }FeSO_4=(1mol/L\times 0.200L)=0.200mol

The chemical equation for the reaction of FeO with sulfuric acid follows:

FeO+H_2SO_4\rightarrow FeSO_4+H_2O

By stoichiometry of the reaction:

If 1 mole of iron (II) sulfate is produced by 1 mole of FeO

So, 0.200 moles of iron (II) sulfate will produce = \frac{1}{1}\times 0.200=0.200mol of FeO

The number of moles is defined as the ratio of the mass of a substance to its molar mass. The equation used is:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

We know, molar mass of FeO = 71.84 g/mol

Putting values in above equation, we get:

\text{Mass of }FeO=(0.200mol\times 71.84g/mol)=14.37g

Hence, the mass of FeO required is 14.37 g

4 0
3 years ago
How many significant figures are in this<br> measurement?<br> 10.006 L
bixtya [17]

Answer: There are 5 significant figures in 10.006L

Explanation: Since there is a decimal point, all the digits after the decimal point also count as significant figures. Below is a key to help yu out:

Not Significant:

- Leading zeroes(in decimal): example- 0.0023= 2 sig figs

- Trailing zeroes with no decimal point: example- 2300= 2 sig figs

Significant:

- middle zeroes: example- 4003= 4 sig figs

-trailing zeroes with decimal point: example- 23.00= 4 sig figs

7 0
3 years ago
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