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4 years ago

What determines the reactivity of a metal?

1 answer:

7 0

The reactivity of a metal is determined by how tightly the metal holds onto the electrons in the outermost energy levels (valence electrons)

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A. 6.07 x 10-15<br> How many significant figures are there in this equation

Harman [31]

Answer:

Explanation:

In scientific notation, the number of integers in the first part will always be the amount of significant figures.

For example,

1) 1.542505 x 10^17 =7 significant figures

1) 1.54 x 10^17 =3 significant figures

8 0

4 years ago

What technique is used to separate the Aluminum soda cans?

Diano4ka-milaya [45]

Answer:

Commonly, Overband Magnets are used to separate steel cans and Eddy Current Separators are used to expel and separate aluminium cans; The Aluminium Cans are discarded into general waste, which is then processed.

Explanation:

8 0

3 years ago

Most of the huge deposits of limestone rock in the earth were formed during Noah's flood. Limestone is a naturally occurring che

maxonik [38]

Cadmium or carbon thanks if i got it right

3 0

3 years ago

Read 2 more answers

Explain, in your own words, what volumic mass is<br><br> plss helpp

AlekseyPX

Answer:

I think that volumic mass is like weight of an object, or like the space it takes up??

Explanation:

Have A Wonderful Day !!

8 0

3 years ago

Calculate the molality of each of the following solutions: (a) 36.2 g of sucrose (C12H22O11) in 323 g of water, m (b) 8.63 moles

Dmitriy789 [7]

Answer:

(a) m = 0.327 m.

(b) m = 4.57 m.

Explanation:

Hello there!

In this case, according to the given information, it turns out possible for us to solve this problem by firstly considering the fact that the molality is computed by dividing the moles of solute by the kilograms of solvent, in this case water; in such a way, we proceed as follows:

(a) We firstly calculate the moles of 36.2 grams of sucrose as its molar mass is 342.3 g/mol:

$\frac{36.2g}{342.3g/mol} =0.106mol$

Next, the kilograms of water in this case are 0.323 kg so that the molality will be:

$m=\frac{0.106mol}{0.323kg}\\\\m=0.327m$

(b) In this case, we directly realize that the kilograms of water are now 1.889 kg so that the molality will be:

$m=\frac{8.63mol}{1.889kg}=4.57m$

Clearly, the both of them in molal, m, units.

Regards!

6 0

3 years ago