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liq [111]
3 years ago
6

Which of the following are not conditions for producing work?

Physics
2 answers:
jeka943 years ago
8 0

Answer:

A and C

Explanation:

We know that

Work done,W=Fd

Where F=Applied force

d=Displacement of object

Momentum, p= mv

It is not necessary that momentum must be greater than force .If momentum is less than force then the work can be produced because work depend upon displacement and applied force.

W=Fdcos\theta

If the value of theta is not equal to zero  the work can be produced if theta is equal to 30 ,45 or 60 degree.

Therefore, it is not necessary that atleast part of the applies force must act along the same line object moves.

If force is greater than weight then, the work can be produced .

If force is less than the weight then, the work cannot be produced .

Hence, the force must be very large.

TEA [102]3 years ago
6 0

Answer:D

Explanation:

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A roller coaster has a "hump" and a "loop" for riders to enjoy (see picture). The top of the hump has a radius of curvature of 1
aivan3 [116]

Answer:

Part a)

F_n = 306 N

Part b)

v = 12.1 m/s

So this speed is independent of the mass of the rider

Explanation:

Part a)

By force equation on the rider at the position of the hump we can say

mg - F_n = ma_c

now we will have

mg - F_n = \frac{mv^2}{R}

F_n = mg - \frac{mv^2}{R}

now we have

F_n = 100(9.81) - \frac{100(9^2)}{12}

F_n = 981 - 675

F_n = 306 N

Part b)

At the top of the loop if the minimum speed is required so that it remains in contact so we will have

F_n + mg = ma_c

F_n = 0 at minimum speed

mg = \frac{mv^2}{R}

v = \sqrt{Rg}

v = \sqrt{15 \times 9.81}

v = 12.1 m/s

So this speed is independent of the mass of the rider

5 0
3 years ago
How much work is done by 0.070 m3 of gas, when the volume remains constant with pressure of 63 x 105 Pa?
stealth61 [152]

Answer:

W = 0 J

Explanation:

The amount of work done by gas at constant pressure is given by the following formula:

W = P\Delta V

where,

W = Work done by the gas

P = Pressure of the gas

ΔV = Change in the volume of the gas

Since the volume of the gas is constant. Therefore, there is no change in the volume of the gas:

W = P(0\ m^3)\\

<u>W = 0 J</u>

5 0
3 years ago
After the box comes to rest at position x1, a person starts pushing the box, giving it a speed v1. when the box reaches position
KiRa [710]

As we know by work energy theorem

total work done = change in kinetic energy

so here we can say that wok done on the box will be equal to the change in kinetic energy of the system

W_p = KE_f - KE_i

initial the box is at rest at position x = x1

so initial kinetic energy will be ZERO

at final position x = x2 final kinetic energy is given as

KE_f = \frac{1}{2}mv_1^2

now work done is given as

W_p = \frac{1}{2}mv_1^2 - 0

so we can say

W_p = \frac{1}{2}mv_1^2

so above is the work done on the box to slide it from x1 to x2

3 0
3 years ago
Can anyone help me plz I m confused with this last question?
Gemiola [76]

Answer:

764728497693575177015915715716245378tr7138

Explanation:

8 0
3 years ago
According to Ohm’s law, the ratio of voltage to current in a conductor is
valina [46]

According to Ohm’s law, the ratio of voltage to current in a conductor is  constant.

Answer: Option A

<u>Explanation:</u>

Ohm's law defines that an electric current flowing through the conductor between two ends is directly proportionate to the voltage at these two points. The introduction of a constant proportionality, resistance, gives a simple mathematical equation describing this relationship. Particularly, Ohm's law also mentions that R is constant in this respect, i.e. not dependent on the current.

                                            I=\frac{V}{R}

Where,  

I is the current conduction in amperes

V is the voltage calculated by the conductor in volts

R is the conductor’s resistance in ohms.

3 0
3 years ago
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