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3 years ago

Which of the following are not conditions for producing work?

Physics

2 answers:

jeka943 years ago

8 0

Answer:

A and C

Explanation:

We know that

Work done,W=Fd

Where F=Applied force

d=Displacement of object

Momentum, p= mv

It is not necessary that momentum must be greater than force .If momentum is less than force then the work can be produced because work depend upon displacement and applied force.

$W=Fdcos\theta$

If the value of theta is not equal to zero the work can be produced if theta is equal to 30 ,45 or 60 degree.

Therefore, it is not necessary that atleast part of the applies force must act along the same line object moves.

If force is greater than weight then, the work can be produced .

If force is less than the weight then, the work cannot be produced .

Hence, the force must be very large.

TEA [102]3 years ago

6 0

Answer:D

Explanation:

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2 years ago

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What determines an object’s thermal energy

Tems11 [23]

Answer:

temperature and mass

Explanation:

The higher the temperature of a given quantity of a substance, more is its thermal energy.

If a substance contains more mass, this also implies that the object has more particles in it . hence, it has high thermal energy.

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3 years ago

water in a cup and a kettle can have the same temperature even though the quantities are different . give reasons

jekas [21]

Answer:

The reason is because both are exposed to a virtually infinite heat sink, due to the virtually infinite mass and of the surrounding environment, compared to the sizes of either the cup or the kettle such that the equilibrium temperature, $T_{(equilibrium)}$ reached is the same for both the cup and the kettle as given by the relation;

$\infty M_{(environ)} \times c_{(environ)} \times (T_2 - T_1) = m_{1} \times c_{(water)} \times (T_3 - T_2) + m_{2} \times c_{(water)} \times (T_4 - T_2)$

Due to the large heat sink, T₂ - T₁ ≈ 0 such that the temperature of the kettle and that of the cup will both cool to the temperature of the environment

Explanation:

4 0

4 years ago

What is the momentum of a vehicle that has a mass of 800 kg and is moving at a velocity of 5 m/s

yarga [219]

Answer:

4000 kg.m/s

Explanation:

p=mv

m=800 kg

v=5 m/s

p=(800)(5)= 4000 kg.m/s

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3 years ago

5. Each of five satellites makes a circular orbit about an object that is much more massive than any of the satellites. The mass

Vikentia [17]

The options of the question are missing. I have attached it.

Answer:

Satellite in option B will have the greatest speed.

Explanation:

From kepplers third law, we know that

V² = GM/R

Thus, v = √(GM/R)

Where;

v is velocity

G is gravitational constant

M is mass

R is radius

Looking at the options, let's start from the first one;

Option A

Here, mass = (1/2)m and radius = R

So, v = √(GM/R) thus v = √(G(m/2)/R) = √(Gm/2R)

Option B

Here, mass = m and radius = (1/2)R

Thus v = √(Gm/(R/2)) = √(2Gm/R)

Option C

Here, mass = m and radius = R

Thus v = √(Gm/R)

Option D

Here, mass = m and radius = 2R

Thus v = √(Gm/(2R))

Now, inspecting all the options, it's clear that option B will have the greatest velocity because it's numerator is the biggest and will in turn lead to higher velocity.

4 0

4 years ago