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amid [387]
3 years ago
5

What is the energy of an electron in the second energy level of hydrogen?

Chemistry
1 answer:
77julia77 [94]3 years ago
7 0

Answer:

-3.4 eV

Explanation:

The second energy level of hydrogen has an electron energy of -3.4 eV. The first level has energy of -13.6 eV but when it jumps from first level of n=1 to second level of n=2, then energy is -3.4 eV from online charts and tables.

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What is the difference between endothermic and exothermic reaction (shortest answer)
max2010maxim [7]

Answer:

An exothermic process releases heat, causing the temperature of the immediate surroundings to rise. An ethothermic process absorbs heat and cools the surroundings. Hope this helped.

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Hormones taken as medicine can harm fish when the hormones end up in waterways. What does this show about the impact of chemical
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The answer to this is C. 
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Can someone please help me with this Chem lab?
Jlenok [28]

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Explanation:

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3 years ago
In one experiment, magnesium metal melts. In a second experiment, magnesium metal ignites as it combines with oxygen. Classify t
joja [24]

Answer:

magnesium metal melts = physical change

magnesium metal ignites = chemical change

Explanation:

<em>Physical changes</em> are those in which the identity of the subtance <u>remains unaltered</u>. No new compounds are formed. They involve generally changes in <u>agreggation states of matter</u>: solid, liquid or gas. The first experiment, in which magnesium metal melts is a physical change because it only changes the state of matter, from solid to liquid, but it is still magnesium metal.

Conversely, <em>chemical changes</em> involve atoms combinations to form new compounds. The second experiment, in which magnesium metal ignites, is a chemical change. After the change, magnesium metal is no longer the metal but a metal oxide.

8 0
3 years ago
47.9 ml hrdrogen is collected at 26° Celsius and 718 torr. Find the volume occupied at STP
Temka [501]

Answer:

41.45 mL

Explanation:

Applying the general gas equation,

PV/T = P'V'/T'............... Equation 1

Where P = Initial pressure of hydrogen, V = Initial volume of hydrogen, T= Initial Temperature of hydrogen, P' = Final pressure of hydrogen, V' = Final Volume of Hydrogen, T' = Final Temperature.

make V' the subject of the equation

V' = PVT'/TP'................ Equation 2

Given: P = 718 torr = (718×133.322) N/m² = 95725.196 N/m², V = 47.9 mL = 0.0479 dm³, T = 26 °C = (26+273) = 299 K, T' = 273 K, P' = 101000 N/m²

Substitute these values into equation 2

V' = ( 95725.196×0.0479×273)/(299×101000)

V' = 0.04145 dm³

V' = 41.45 mL

4 0
3 years ago
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