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3 years ago

A town has a population of 2000 and grows at 4% every year. What will be the

Mathematics

1 answer:

natka813 [3]3 years ago

6 0

Answer:

$\frac{4}{?100} \times \frac{2000}{?1} = 80 \\ \\ 2000 + 80 = 2080 \\ \\ 2080 \times 15 = 31200$

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Find the approximate side length of a square game board with an area of 157 in^2.

Nesterboy [21]

Answer:

12.52 in.

Step-by-step explanation:

Area of square(A)=157in^2

length of square (l)=?

we know,

A=l^2

or,sqrt 157=l

12.52 in=l

3 0

2 years ago

Can someone please help if you can you are amazing and awesome

Ainat [17]

Answer:

domain(-4,6) and range(-1, 8)

Step-by-step explanation:

domain is an imput on x axis, and range on y

4 0

3 years ago

bobby hopes that he will some day be more than 70 inches tall. he is currently 61 inches tall how many inches , x , does bobby n

leonid [27]

10 inches would make him taller than 70, 9 inches would make him exactly 70

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3 years ago

There are currently 17 frogs in a (large) pond. The frog population grows exponentially, tripling every 6 days. How long will it

Tema [17]

Answer:

t=11,11 days

Step-by-step explanation:

F=frogs poblation, t=time, be the variables dF/dt = KF, dF/F=Kdt, integrating $\int\limits^ {} \, dF/F =K\int\limits^ {} \, dt$ ⇒ LnF=Kt+c, $F=ce^{Kt}$ ; Knowing t=0, F=17 and t=6 F=51 (tripling every 6 days (17*3)), $F=ce^{K0} = F=c=17; F=17e^{6K} =51$ ⇒ $e^{6K} =51/17; K6=ln\frac{51}{17} ; K=ln\frac{51}{17}/6=0.183$ , so $F=17e^{0,183t}$ , now if F=130, t=? we have:

$130=17e^{0.183t} =e^{0.183t} =130/17; 0.183t=ln(130/17); t=ln(130/17)/0.183 = 11,11$

8 0

3 years ago

What is the following product? Sqr5x^8y^2 sqr10x^3 sqr12y

PSYCHO15rus [73]

Step-by-step explanation:

$\sqrt{5 {x}^{8} {y}^{2} } \times \sqrt{10 {x}^{3} } \times \sqrt{12y} \\ \\ = {x}^{4} y \sqrt{5} \times x \sqrt{10x} \times 2 \sqrt{3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 10x \times 3y} \\ \\ = 2 {x}^{5} y \sqrt{5 \times 5 \times 2x \times 3y} \\ \\ = 2 {x}^{5} y \times 5\sqrt{ 2x \times 3y} \\ \\ = 10 {x}^{5} y \sqrt{6xy} \\$

4 0

3 years ago