Question

A metal sphere with a charge of +25 x 10-9 C is placed 2 m away from another metal sphere which carries a charge of +10 x 10^-9 C. What is the magnitude and direction of the electric force between the two metal spheres?

Answer 1

Answer:

F = 5.625 10⁻⁷ N

Explanation:

For this exercise we use coulomb's law

          F =  $k \ \frac{q_1q_2}{r^2}$

where k is the Coulomb constant which is equal to 9 10⁺⁹ N m² /C²

as the charge on the two spheres has the same sign, the force is repulsive,

let's calculate

          F = 9 10⁹ 25 10⁻⁹ 10 10⁻⁹ / 2²

          F = 5.625 10⁻⁷ N