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2 years ago

Is the product of two binomials always a trinomial? Give an example to support your answer.

2 answers:

4 0

(a+b)(a-b)=a^2-ab+ab-b^2=a^2-b^2. This is a binomial. Hence, it is not always true that the product of two binomials is a trinomial.

nydimaria [60]2 years ago

3 0

Answer:

Consider: (a+b)(a-b)=a^2-ab+ab-b^2=a^2-b^2. This is a binomial. Hence, it is not always true that the product of two binomials is a trinomial.

Step-by-step explanation:

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Tim took a random survey of 20 sixth graders and 20 eighth graders. He asked how many hours a week each played sports. His data

34kurt

Answer: 4 hours

Step-by-step explanation:

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3 years ago

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3 years ago

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victus00 [196]

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3 years ago

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A random sample of 100 automobile owners in thestate of Virginia shows that an automobile is driven onaverage 23,500 kilometers

Anastaziya [24]

Answer:

a) 22497.7 < μ< 24502.3

b) With 99% confidence the possible error will not exceed 1002.3

Step-by-step explanation:

Given that:

Mean (μ) = 23500 kilometers per year

Standard deviation (σ) = 3900 kilometers

Confidence level (c) = 99% = 0.99

number of samples (n) = 100

a) α = 1 - c = 1 - 0.99 = 0.01

$\frac{\alpha }{2} =\frac{0.01}{2}=0.005\\ z_{\frac{\alpha }{2}}=z_{0.005}=2.57$

Using normal distribution table, $z_{0.005$ is the z value of 1 - 0.005 = 0.995 of the area to the right which is 2.57.

The margin of error (e) is given as:

$e= z_{0.005}\frac{\sigma}{\sqrt{n} } = 2.57*\frac{3900}{\sqrt{100} } =1002.3$

The 99% confidence interval = (μ - e, μ + e) = (23500 - 1002.3, 23500 + 1002.3) = (22497.7, 24502.3)

Confidence interval = 22497.7 < μ< 24502.3

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3 years ago

Function or not a function

Aliun [14]

Answer:

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Step-by-step explanation:

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2 years ago

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