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TiliK225 [7]
3 years ago
10

Discuss the nature of materials causing turbidity in

Engineering
2 answers:
natta225 [31]3 years ago
7 0
A if not B i believe
Anestetic [448]3 years ago
5 0

Answer:

a

Explanation:

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At a given point in a supersonic wind tunnel, the pressure and temperature are 5×104 N/m2 and 200 K, respectively. The total pre
Ne4ueva [31]

Answer:

The Mach number is 2.866

Total temperature To = 528.524K

Explanation:

Pressure (P)= 5 * 10^4 N/m^2

Total pressure (Po) =  1.5 * 10^6 N/m^2

Temperature (T) = 200K

For air, r= 1.4

To find the Mach number we use:

Po/P = [1 + (r - 1/2) M^2] ^ r^/^r^-^1

1.5 * 10^6 / 5 * 10^4 =[ 1 + (1.4 -1 /2) (M^2) ] ^ 1^.^4^/^1^.^4^-^1

0.3 * 10^2 = (1 + 0.2M^2) ^3^.^5

(0.3 * 10^2)^(1/3.5) = 1 + 0.2M^2

2.6426 = 1 +0.2M^2

2.6426 - 1 = 0.2M^2

1.6426 = 0.2M^2

M^2 = 1.6426/0.2

M = sqrt(1.6426/0.2)

M = 2.866

To find Total Temperature :

To/T = (Po/P)^r^-^1^/^8) [tex][tex] To/200 = (1.5*10^6 / 5*10^4)^ 1^.^4^-^1^/^1^.^4)

To/200 = (0.3 * 10^2)^0^.^2^8^5^7

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3 years ago
An AC circuit has a resistor, capacitor and inductor in series with a 120 V, 60 Hz voltage source. The resistance of the resisto
aliina [53]

Answer:

(i) 3.5385 ohm, 3.768 ohm (ii) 39.89 A (III) 4773.857 W (vi) 348 var (vii) 0.9973 (viii) 4.1796°

Explanation:

We have given voltage V =120 volt

Frequency f=60 Hz

Resistance R =3 ohm

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Capacitance C =0.00075 farad

(i) reactance of of inductor X_L=\omega L=2\pi fL=2\times 3.14\times 60\times 0.01=3.768ohm

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(ii) Total impedance Z=\sqrt{R^2+(X_L-X_C)^2}=\sqrt{3^2+(3.768-3.5385)^2}=3.008ohm

Current i=\frac{V}{Z}=\frac{120}{3.008}=39.89A

(viii) power factor cos\Phi =\frac{R}{Z}=\frac{3}{3.008}=0.9973

(VII) cos\Phi =0.9973

\Phi =4.1796^{\circ}

So power factor angle is 4.1796°

(iii) Apparent power P=VICOS\Phi =120\times 39.89\times 0.9973=4773.875W

(vi) Reactive power Q=VISIN\Phi =120\times 39.89\times SIN4.17^{\circ}=348var

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