Body composition is?
2 answers:
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Answer:
ΔK = -6 10⁴ J
Explanation:
This is a crash problem, let's start by defining a system formed by the two trucks, so that the forces during the crash have been internal and the moment is preserved
initial instant. Before the crash
p₀ = m v₁ + M 0
final instant. Right after the crash
p_f = (m + M) v
p₀ = p_f
mv₁ = (m + M) v
v =
we substitute
v = 3
v = 1.0 m / s
having the initial and final velocities, let's find the kinetic energy
K₀ = ½ m v₁² + 0
K₀ = ½ 20 10³ 3²
K₀ = 9 10⁴ J
K_f = ½ (m + M) v²
K_f = ½ (20 +40) 10³ 1²
K_f = 3 10⁴ J
the change in energy is
ΔK = K_f - K₀
ΔK = (3 - 9) 10⁴
ΔK = -6 10⁴ J
The negative sign indicates that the energy is ranked in another type of energy
Hi there!
To calculate the tension, we must calculate the acceleration of the system.
Begin with a summation of forces:
∑F = -M₁gsinФ + T - T + M₂g
Simplify and solve for acceleration: (Tensions cancel out)
Plug in values. Let g = 10 m/s²
Now, to find tension, let's sum up the forces acting on ONE block. For simplicity, we can look at the hanging block:
∑F = -T + W
ma = -T + W
Rearrange to solve for T:
T = W - ma
We know the acceleration, so plug in the values:
T = (8)(10) - (8)(5.91) = 32.73 N