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Lapatulllka [165]
2 years ago
11

Two metal spheres are made of the same material and have the same diameter, but one is solid and the other is hollow. If their t

emperature is increased by the same amount:_______.
A) the solid sphere becomes heavier and the hollow one lighter.
B) the solid sphere becomes bigger than the hollow one.
C) the hollow sphere becomes bigger than the solid one.
D) the two spheres remain of equal size.
E) the solid sphere becomes lighter and the hollow one heavier.
Physics
1 answer:
galina1969 [7]2 years ago
5 0

Answer:

D) the two spheres remain of equal size.

Explanation:

  • Since the body of the sphere is made up of both the same material. Thus the orientation will not affect the expansion. That is solid upon solid and hollow upon the hollow sphere. Hence it can be said that both the sphere expands and is due to the material used for making both of them is the same.
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Upper A 16​-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away f
Sav [38]

Answer:

The ladder is moving at the rate of 0.65 ft/s

Explanation:

A 16​-foot ladder is leaning against a building. If the bottom of the ladder is sliding along the pavement directly away from the building at 2 ​feet/second. We need to find the rate at which the top of the ladder moving down when the foot of the ladder is 5 feet from the​ wall.

The attached figure shows whole description such that,

x^2+y^2=256.........(1)

\dfrac{dx}{dt}=2\ ft/s

We need to find, \dfrac{dy}{dt} at x = 5 ft

Differentiating equation (1) wrt t as :

2x.\dfrac{dx}{dt}+2y.\dfrac{dy}{dt}=0

2x+y\dfrac{dy}{dt}=0

\dfrac{dy}{dt}=-\dfrac{2x}{y}

Since, y=\sqrt{256-x^2}

\dfrac{dy}{dt}=-\dfrac{2x}{\sqrt{256-x^2}}

At x = 5 ft,

\dfrac{dy}{dt}=-\dfrac{2\times 5}{\sqrt{256-5^2}}

\dfrac{dy}{dt}=0.65

So, the ladder is moving down at the rate of 0.65 ft/s. Hence, this is the required solution.

8 0
3 years ago
Behavior that benefits others is called behavior
Ratling [72]
Prosocial Behavior.
5 0
3 years ago
A force F is used to raise a 4-kg mass M from the ground to a height of 5 m. What is the work done by the force F? (Note: sin 60
miskamm [114]

Answer:

Answer:196 Joules

Explanation:

Hello

Note:  I think the text in parentheses corresponds to another exercise, or this is incomplete, I will solve it with the first part of the problem

the work  is the product of a force applied to a body and the displacement of the body in the direction of this force

assuming that the force goes in the same direction of the displacement, that is upwards

W=F*D (work, force,displacement)

the force necessary to move the object will be

F=mg(mass *gravity)\\F=4kgm*9.8\frac{m}{s^{2} }\\ F=39.2 Newtons\\replace\\\\W=39.2 N*5m\\W=196\ Joules

Answer:196 Joules

I hope it helps

5 0
3 years ago
The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given b
Mnenie [13.5K]

Explanation:

The quantity of charge Q in coulombs (C) that has passed through a point in a wire up to time t (measured in seconds) is given by :

Q=t^3-2t^2+4t+4

We need to find the current flowing. We know that the rate of change of electric charge is called electric current. It is given by :

I=\dfrac{dQ}{dt}\\\\I=\dfrac{d(t^3-2t^2+4t+4)}{dt}\\\\I=3t^2-4t+4

At t = 1 s,

Current,

I=3(1)^2-4(1)+4\\\\I=3\ A

So, the current at t = 1 s is 3 A.

For lowest current,

\dfrac{dI}{dt}=0\\\\\dfrac{d(3t^2-4t+4)}{dt}=0\\\\6t-4=0\\\\t=0.67\ s

Hence, this is the required solution.

7 0
3 years ago
Match to the correct answers
yarga [219]
A. You measure power on watts.
B. Non-renewable
C.renewable
D. Joules
E. Fossil fuels
8 0
3 years ago
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