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garik1379 [7]
3 years ago
9

(20 points) i) An absorption intensity of 1.00 (in arbitrary units) is observed for the maximum peak of the 1:2:1 triplet of the

1H resonance of the CH3 group of ethanol dissolved in CCl4 at 1.00 M concentration using a 160 MHz NMR instrument at 300 K. What concentration of ethanol would you need to measure the same signal size if the measurement is performed with a 450 MHz NMR instrument at 2.2 K
Chemistry
1 answer:
laiz [17]3 years ago
5 0

Answer:

Concentration of ethanol required =  48.476 M

Explanation:

Given that:

the absorption intensity = 1.00

Molarity of ethanol = 1M

NMR instrument used = 160 MHz

Temperature used = 300 K

The required concentration of ethanol can be determined as follows:

=  ( 1 \ M \times \dfrac{160\ MHz }{450 \ MHz}) \times \dfrac{300 \ K}{2.2\ K}

=  ( 1 \ M \times 0.3555 ) \times136.36}

= 48.476 M

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