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Alika [10]
3 years ago
13

An obect is placed 20cm from a convex mirror of focal length 12cm. where does the image form?

Physics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

7.5 cm behind the mirror

Explanation:

Applying,

Using the real is positive convection: All real distance from the mirror are positive

1/f = 1/v+1/u................. Equation 1

Where f = focal length of the mirror, v = image distance, u = object distance

From the question,

f = -12 cm, u = 20 cm

substitute these value into equation 1

1/(-12) = (1/20)+1/v

(-1/12)-(1/20) = 1/v

1/v = (-5-3)/60

1/v = -8/60

v = -60/8

v = -7.5 cm

Hence the image is formed 7.5 cm behind the mirror.

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A 70 ft rope hangs from a helicopter above this room. The rope has a mass per unit length of 2 lb/ft. In order to be rescued fro
Mrac [35]

Answer:

The work done to get you safely away from the test is  2.47 X 10⁴ J.

Explanation:

Given;

length of the rope, L = 70 ft

mass per unit length of the rope, μ = 2 lb/ft

your mass, W = 120 lbs

mass of the 70 ft rope  = 2 lb/ft x 70 ft

                                         = 140 lbs.

Total mass to be pulled to the helicopter, M = 120 lbs  + 140 lbs  

                                                                       = 260 lbs

The work done is calculated from work-energy theorem as follows;

W = Mgh

where;

g is acceleration due gravity = 32.17 ft/s²

h is height the total mass is raised = length of the rope = 70 ft

W = 260 Lb x 32.17 ft/s²  x 70 ft

W = 585494 lb.ft²/s²

1 lb.ft²/s² = 0.0421 J

W = 585494 lb.ft²/s²  = 2.47 X 10⁴ J.

Therefore, the work done to get you safely away from the test is  2.47 X 10⁴ J.

4 0
2 years ago
The flow control circuit design that can best control an overrunning load is the ____ circuit.
lara31 [8.8K]

The meter out circuit is the flow control circuit design that can most effectively control an overrunning load.

The meter-out circuit can be very accurate, but are not efficient. The meter-out circuit can control overrunning as well as opposing loads while the other one method must be used with opposing loads only. The choice of flown control valve method and the location of the flow control in the circuit are dependent on the type of application being controlled.

<h3>What is a Circuit ?</h3>

In electronics, a circuit is a complete circular conduit through which electricity flows. A simple circuit consists of conductors, a load, and a current source. The term "circuit" broadly refers to any continuous path via which electricity, data, or a signal might flow.

  • The directional valve shifts, causing the actuator to move faster than pump flow can fill it due to an overrunning load. Oil is leaking from one side, whereas there is none on the other.

Hence, flow control circuit design that can best control an overrunning load is the opposing circuit

Learn more about Circuit here:

brainly.com/question/26064065

#SPJ4

3 0
2 years ago
A large asteroid of mass 98700 kg is at rest far away from any planets or stars. A much smaller asteroid, of mass 780 kg, is in
Citrus2011 [14]

Answer:

1.81 x 10^-4 m/s

Explanation:

M = 98700 kg

m = 780 kg

d = 201 m

Let the speed of second asteroid is v.

The gravitational force between the two asteroids is balanced by the centripetal force on the second asteroid.

\frac{GMm}{d^{2}}=\frac{mv^2}{d}

v=\sqrt{\frac{GM}{d}}

Where, G be the universal gravitational constant.

G = 6.67 x 10^-11 Nm^2/kg^2

v=\sqrt{\frac{6.67 \times 10^{-11}\times 98700}{201}}

v = 1.81 x 10^-4 m/s

7 0
3 years ago
Write atleast name of five devices which work under the principles of physics
Colt1911 [192]
You could say almost anything.
For example:
phones,
cars,
computers,
clocks,
hydraulics,
bicycles,
the hadron collider,
Planes,
and so on.
3 0
3 years ago
Read 2 more answers
A box of mass m1 rests on a smooth, horizontal floor next to a box of mass m2. Suppose the force of 20.0 N pushes on two boxes o
meriva

Answer:

Explanation:

Given

acceleration of system a =1.2 m/s^2

Normal Force N=4.45 N

Force exerted F=20 N

Thus

F=(m_1+m_2)a

\frac{20}{1.2}=m_1+m_2

16.67=m_1+m_2-------1

Normal reaction N=m_2a

4.45=m_2\times 1.2

m_2=3.70 kg

therefore m_1=16.67-3.70

m_1=12.96 kg

8 0
3 years ago
Read 2 more answers
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