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3 years ago

What factors are affected by the petrol crisis ?

Physics

2 answers:

AURORKA [14]3 years ago

8 0

Answer:

<h2>1. Crude Oil Costs. Crude oil pricing is often what influences heating oil prices the most. </h2><h2>2. Supply and Demand.</h2><h2>3. Futures and Commodities Traders. </h2><h2>4. Changes in the Energy Industry. </h2><h2>5. Seasonal Demands. </h2><h2>6. The Weather. </h2><h2>7. Natural Disasters and Politics. </h2>

Explanation:

<h2>Hopes this helps. Mark as brainlest plz!</h2>

Sergeeva-Olga [200]3 years ago

3 0

Explanation:

Crude Oil Costs. Crude oil pricing is often what influences heating oil prices the most. ...

Supply and Demand. ...

Futures and Commodities Traders. ...

Changes in the Energy Industry. ...

Seasonal Demands. ...

The Weather. ...

Natural Disasters and Politics. ...

Your Neighborhood.

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How is a magnetic field generated?

alekssr [168]

It would be B I think

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3 years ago

A certain amount of grass gets 10,000 kcal of energy from the sun. How much energy will be available to the next trophic level?

Nesterboy [21]

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4 years ago

Figure 8-56 shows a solid, uniform cylinder of mass 7.00 kg and radius 0.450 m with a light string wrapped around it. A 3.00-N t

AVprozaik [17]

Answer:

a) The cylinder has an angular acceleration of 3.810 radians per square second, b) The frictional force has a magnitude of 9 newtons and has the same direction of tension force.

Explanation:

The external force exerted on string creates a tension force that tries to move the cylinder in translation, but it is opposed by the friction force between cylinder and ground that generates rolling on cylinder. The Free Body Motion on cylinder-string system is presented below as attachment. Given that cylinder is a rigid body in planar motion, two equations of equilibrium for translation and an equation of equilibrium for rotation are needed to represent the system, which are now described:

$\Sigma F_{x} = T + f = M\cdot R\cdot \alpha$

$\Sigma F_{y} = N - M\cdot g = 0$

$\Sigma M_{G} = (T-f)\cdot R = I_{G}\cdot \alpha$

Where:

$T$ - Tension, measured in newtons.

$f$ - Friction force, measured in newtons.

$M$ - Mass of the cylinder, measured in kilograms.

$R$ - Radius of the cylinder, measured in meters.

$\alpha$ - Angular acceleration, measured in radians per square second.

$N$ - Normal force from ground exerted on cylinder, measured in newtons.

$g$ - Gravitational acceleration, measured in meters per square second.

$I_{G}$ - Moment of inertia of the cylinder with respect to its center of mass, measured in kilogram-square meters.

The moment of inertia of the cylinder is:

$I_{G} = \frac{1}{2}\cdot M\cdot R^{2}$

a) The angular acceleration is determined by solving on first and third equation after eliminating friction force:

$f = M\cdot R \cdot \alpha - T$

$(T-M\cdot R\cdot \alpha+T) \cdot R = I_{G}\cdot \alpha$

$2\cdot T\cdot R = (I_{G} + M\cdot R^{2})\cdot \alpha$

$\alpha = \frac{2\cdot T\cdot R}{I_{G}+M\cdot R^{2}}$

$\alpha = \frac{2\cdot T \cdot R}{\frac{1}{2}\cdot M\cdot R^{2}+M\cdot R^{2} }$

$\alpha = \frac{4\cdot T}{3\cdot M\cdot R}$

If $T = 3\,N$ , $M = 7\,kg$ and $R = 0.45\,m$ , then:

$\alpha = \frac{4\cdot (3\,N)}{(7\,kg)\cdot (0.45\,m)}$

$\alpha = 3.810\,\frac{rad}{s^{2}}$

The cylinder has an angular acceleration of 3.810 radians per square second.

b) The magnitude of the frictional force can be determined with the help of the following expression:

$f = M\cdot R \cdot \alpha - T$

Given that $T = 3\,N$ , $M = 7\,kg$ , $R = 0.45\,m$ and $\alpha = 3.810\,\frac{rad}{s^{2}}$ , the magnitude of the friction force is:

$f = (7\,kg)\cdot (0.45\,m)\cdot \left(3.810\,\frac{rad}{s^{2}} \right)-3\,N$

$f = 9\,N$

The frictional force has a magnitude of 9 newtons and has the same direction of tension force.

5 0

4 years ago

When an electric current runs through a wire a magnetic field is included where?

Luba_88 [7]

I think its inside the loop i had this lesson last week :)

8 0

3 years ago

The atomic radius of metal X is 1.20 × 102 picometers (pm) and a crystal of metal X has a unit cell that is face-centered cubic.

pickupchik [31]

The density of the metal can be determined through the formula [n*MW]/ Na*[a^3] . substituting, we get,

<span>d = [n*MW]/ Na*[a^3]
</span><span>d = [4 atoms*42.3 g/mol]/ [6.022 x 1023atoms/mol* (sqrt 8 *1.20x10-10)^3]
</span>d = 0.719 g/cm3

7 0

3 years ago