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FrozenT [24]
3 years ago
7

Consider the chemical equations shown here. Upper N Upper O (g) + Upper O Subscript 3 Baseline (g) right arrow Upper N Upper O S

ubscript 2 Baseline (g) + Upper O Subscript 2 Baseline (g) delta Upper H Subscript 1 Baseline = negative 198.9 kilojoules. StartFraction 3 Over 2 EndFraction Upper O Subscript 2 Baseline (g) right arrow Upper O Subscript 3 Baseline (g) delta Upper H Subscript 2 Baseline = 142.3 kilojoules. Upper O (g) right arrow one half Upper O Subscript 2 Baseline (g) delta Upper H Subscript 3 Baseline = negative 247.5 kilojoules. What is Delta.Hrxn for the reaction shown below? Upper n upper O (g) plus upper O (g) right arrow upper N upper O subscript 2 (g).
Chemistry
2 answers:
Bas_tet [7]3 years ago
8 0

Answer:

-867.7 kJ on edge

Explanation:

just took the test

alexandr1967 [171]3 years ago
6 0

Answer:

-304.1

Explanation

just took the test

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The reaction CO2(g) → C(s) + O2(g) is a decomposition reaction.<br><br> True<br> False
Lyrx [107]

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3 years ago
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A potential energy diagram is shown. A graph is plotted with Potential Energy in KJ on the y axis and Reaction Pathway on the x
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3 0
4 years ago
Propose a structure for an aromatic hydrocarbon, C9H12, that can form two C9H11Cl products on substitution of a hydrogen on the
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Answer:

Explanation:

From the given study,

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the first process we suppose to carry out is to calculate the double bond equivalence.

So, the double bond equivalence DBE = {N_C+1-(\dfrac{(N_H+N_{Cl})-N_H}{2})  }

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The substitutional products of the aromatic hydrocarbon C9H12 can be seen in the attached file below.

3 0
3 years ago
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4 years ago
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