Write a recursive formula for the

Mathematics

1 answer:

Olenka [21]3 years ago

8 0

Answer: Adding 15 each time

You might be interested in

Name three pairs of numbers that have 5 as their greatest common factor. Use each number only once in your answer.

GenaCL600 [577]

Answer:

Step-by-step explanation:

10,15,20. Each using 5 as the GCF

25,30,35. The biggest GCF in 25 is 5, in 30 is 6, in 35 7.

So we can't use 6 or 7 as the GCF,

But, we can use 5 as the GCF.

Same with 40, 45, 50.

The GCF of 40 is 8, for 45 is 9, and for 50 is 10.

But then again, those are not common, so 5 it is again.

And this could keep on going but watch out, it might fail! c:

4 0

3 years ago

How many hours did Diana work of she was paid $45.50

JulijaS [17]

I think it would be C because the equation is y=7x. y=7x is also equal to x=1/7y. If y=45.50, then you would have to divide y by 7, which would equal 6.5.

8 0

3 years ago

Read 2 more answers

Please please help me

Gekata [30.6K]

Answer:

$\large\boxed{\dfrac{\boxed{8}}{81}}$

Step-by-step explanation:

$\text{If}\ a_1,\ a_2,\ a_3,\ a_4,\ ...,\ a_n\ \text{is the geometric sequence, then}\\\\\dfrac{a_2}{a_1}=\dfrac{a_3}{a_2}=\dfrac{a_4}{a_3}=...=\dfrac{a_n}{a_{n-1}}=constant=r-\text{common ration}.\\\\\text{We have}\ \dfrac{1}{2},\ \dfrac{1}{3},\ \dfrac{2}{9},\ \dfrac{4}{27},\ ...\\\\\dfrac{\frac{1}{3}}{\frac{1}{2}}=\dfrac{1}{3}\cdot\dfrac{2}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{2}{9}}{\frac{1}{3}}=\dfrac{2}{9}\cdot\dfrac{3}{1}=\dfrac{2}{3}\\\\\dfrac{\frac{4}{27}}{\frac{2}{9}}=\dfrac{4}{27}\cdot\dfrac{9}{2}=\dfrac{2}{3}$

$\bold{CORRECT}\\\\\dfrac{x}{\frac{4}{27}}=\dfrac{2}{3}\qquad\text{multiply both sides by}\ \dfrac{4}{27}\\\\x=\dfrac{2}{3}\cdot\dfrac{4}{27}\\\\x=\dfrac{8}{81}$