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stepladder [879]
3 years ago
8

Write a recursive formula for the

Mathematics
1 answer:
Olenka [21]3 years ago
8 0

Answer: Adding 15 each time

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The university is on a bearing of 050 degrees from the stadium and 300 degrees from the hospital. Mark the position of the unive
Licemer1 [7]

Answer:

Check Explanation

Step-by-step explanation:

The map isn't available, but, one can draw this bearings with the descriptions given

Angles for bearings are usually drawn, reading from the north direction.

A sketch of the described bearings and locations of the stadium, university and the hospital is presented in the attached image to this question.

For the sketch on the map.

On The map, draw a four-cardinal points' cross at the stadium draw a line from the bearing 050° from the stadium's four cardinal points' cross. Leave the line as it is.

Then, draw another four cardinal points' cross at the hospital and draw a line from the bearing 300° from the hospital's four cardinal points' cross.

Wherever the line from the hospital meets the line from the stadium, is where the University is located.

Hope this Helps!!!!

6 0
3 years ago
Simplify. 14+{−2+3[1+3(−6−2)]} show how to solve as well with answer
frez [133]
It’s -57 thank me later
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Please help me I love u
r-ruslan [8.4K]
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boyakko [2]

Answer:

black socks = 36

total socks 48

apple's = 6

strawberry sweets = 72

2nd class = 24

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total student 1900

8 0
2 years ago
URGENT! WILL GIVE BRAINLY FOR CORRECT ANSWER
Minchanka [31]

Answer:

sorry if im wrong i think wrong numbers. plz check

Step-by-step explanation:

The center of dilation of the question is (-4,-3) .

let say that

x0=-4

y0=-3

Label the image A'B'C'

The new coordinate would be

A(-4,-1)

x=4

y=-1

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-1 +3)

y'=-3 +4= 1

______________________________

B(-4,-3)

x=-4

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-4 +4)

x'=-4

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

______________________________

C(-1,-3)

x=-1

y=-3

x'=x0+ 2(x - x0)

x'= -4+ 2(-1 +4)

x'=-4 +6= 2

y'=y0+ 2(y - y0)

y'= -3+ 2(-3 +3)

y'=-3

A'(-4,1)

B'(-4,-3)

C'(2,-3)

3 0
2 years ago
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