The question is incomplete, here is the complete question:
Consider the reaction
Initially,
= 3.60 M; at equilibrium
. Calculate the equilibrium concentration for 
<u>Answer:</u> The equilibrium concentration of ammonia is 2.8 M
<u>Explanation:</u>
We are given:
Initial concentration of
= 3.60 M
Initial concentration of
= 3.60 M
For the given chemical equation:

Initial: 3.60 3.60
At eqllm: 3.60-4x 3.60-7x 2x 6x
We are given:
Equilibrium concentration of
= 0.60 M
Evaluating the value of 'x'

So, equilibrium concentration of 
Hence, the equilibrium concentration of ammonia is 2.8 M
Can I know which grade are uh, according to the grade only visible to check
Answer:
Phase C - Liquid State
Phase E - Gaseous State
Explanation:
Usually, in phases of water, we have the following;
When temperature is less than zero, it is said to be in its solid phase as ice.
When temperature is between 0 to 100, we can say it is in the liquid phase as water.
When temperature is above 100°C, It is said to be in the gaseous phase as vapour.
From the diagram;
Phase C is the only liquid state because it falls between temperature of 0°C and 100°
Also, only phase E is in the gaseous phase because the temperature is above 100°C.
We can determine the empirical formula by first converting each of the grams to moles. remember to do this, first, we need the molar mass of the molecules which can be calculated by adding the mass of the atoms from the periodic table.
molar mass of CO2= 44.0 g/mol
molar mass of H2O= 18.02 g/mol
now, lets determine the grams of each atom
Carbon: 23.98 g x (12.011 g / 44.01 g) = 6.54 g C
Hydrogen: 4.91 g x (2.0158 g / 18.02 g) = 0.55 g H
Oxygen: 10.0 - (6.54 + 0.55) = 2.91 g O
Now let's convert each mass to moles.
C: 6.54 g / 12.01 g / mol = 0.54 mol
H: 0.55 g / 1.01 g/mol = 0.54 mol
O: 2.91 g / 16.00 g/mol = 0.18 mol
now that we have the moles of each atom, we need to divide them by the smallest value to find the ration. If you do not get the whole number, you need to multiply until to get a whole number.
C: 0.54 mol / 0.18 mol = 3
H: 0.54 mol / 0.18 mol = 3
O: 0.18 mol / 0.18 mol = 1
empirical formula--> C₃H₃O
Answer:
C
Explanation:
the enthalpy of reaction is independent of the reaction path