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artcher [175]
2 years ago
5

If the column of mercury in a barometer stands at 72.6 cm, what is the atmospheric pressure?

Physics
1 answer:
lakkis [162]2 years ago
6 0

Answer:pressure = density * acceleration due to gravity * height

H=72.6cm= 0.726m

P=0.726*13.6*10^3*9.8

P=96761.28Pa

Explanation:

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6 0
3 years ago
A 12 kg box is pulled across the floor with a 48 N horizontal force. If the force of friction is 12 N, what is the acceleration
Oksi-84 [34.3K]

Answer:

The acceleration of the box is 3 m/s²

Explanation:

Given;

mass of the box, m = 12 kg

horizontal force pulling the box forward, Fx = 48 N

frictional force acting against the box in opposite direction, Fk = 12 N

The net horizontal force on the box, F = 48 N - 12 N

The net horizontal force on the box, F = 36 N

Apply Newton's second law of motion to determine the acceleration of the box;

F = ma

where;

F is the net horizontal force on the box

a is the acceleration of the box

a = F / m

a = 36 / 12

a = 3 m/s²

Therefore, the acceleration of the box is 3 m/s²

7 0
3 years ago
Explain why saucepans are much more common with plastic handles than metal handles.
horrorfan [7]
Because it’s cheaper and efficient
3 0
3 years ago
Read 2 more answers
The electrical resistance of an element in a platinum resistance thermometer at 100°c, 0°c and room temperature are 75.00Ω, 63.0
Dominik [7]

Answer:

16.6 °C

Explanation:

From the question given above, the following data were obtained:

Temperature at upper fixed point (Tᵤ) = 100 °C

Resistance at upper fixed point (Rᵤ) = 75 Ω

Temperature at lower fixed point (Tₗ) = 0 °C

Resistance at lower fixed point (Rₗ) = 63.00Ω

Resistance at room temperature (R) = 64.992 Ω

Room temperature (T) =?

T – Tₗ / Tᵤ – Tₗ = R – Rₗ / Rᵤ – Rₗ

T – 0 / 100 – 0 = 64.992 – 63  / 75 – 63

T / 100 = 1.992 / 12

Cross multiply

T × 12 = 100 × 1.992

T × 12 = 199.2

Divide both side by 12

T = 199.2 / 12

T = 16.6 °C

Thus, the room temperature is 16.6 °C

6 0
2 years ago
"Today you will use this chart to help you identify some common minerals," instructed Mr. Grant, Jimmy's teacher. Each group of
scoray [572]

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