2 HBr + Mg(OH) 2 yields Mg(Br) 2 + 2 H2O
M1V1 = M2V2
(0.245 M)(37.5 mL) = (M2)(18.0 mL)
9.1875 = (M2)(18.0 mL)
9.1875/(18.0 mL) = (M2)(18.0 mL)/(18.0 mL)
0.51041
this is not the complete answer as the mol to mol ratio must be considered!
For every 2 mols of HBr there is 1 mole of <span>Mg(OH)2; ratio = 2:1
</span>0.51041 / 2 = 0.25520
M2 = 0.25520
0.25520 M of<span> Mg(OH)2 solution</span>
The main difference between a covalent compound and an ionic compound is the type of elements used. In a covalent compound, a nonmetal bonds with another nonmetal (e.g. H20, NH3, CH4).
In an ionic compound, a metal bonds with a nonmetal (e.g.NaCl, KCl, MgCl2). What makes an ionic compound binary is the amount of atoms used. This includes any ionic compounds that has two atoms such as NaCl and KCl.
Note that although MgCl2 has two elements, it does not have the same amount of atoms. Mg is one atom and Cl has a subscript of 2 which makes chlorine have two atoms.
Hope this helps!!!
Kepler stated three laws of planetary motion.
First law states that the pathway of a planet is an ellipse with the Sun at one of the foci.
Second law states that an imaginary line joining the Sun and a planet sweeps out equal areas during equal lengths of time.
Third law states that the square of the period of the orbit of a planet is directly proportional to the cube of the length of the distance from the Sun.
Therefore, the answer is that Kepler's second law of planetary motion states that planets cover the same area during equal time periods.
Answer : 13.64 mL
Explanation : The reaction requires 13.64 mL of NaOH
From the reaction we know that oxalic acid requires two moles of NaOH so we have to calculate the number of moles of both.
0.150 L X 0.1500 moles/L = 2.25 X 
So the moles of NaOH will be 2 X (2.25 X ) = 4.5 X
Now, we know the concentration of NaOH as 0.330 M
4.5 X moles / 0.330 moles/L = 0.01364 L or 13.64 mL
So, the volume of NaOH needed to neutralize oxalic acid will be 13.64 mL
Answer:
Explanation:
density is the amount of weight/mass packed into a specific volume of material so i believe that is right
