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jolli1 [7]
3 years ago
11

HLP PLZ. explain why you need to use more than one property to identify a mineral.

Chemistry
1 answer:
marin [14]3 years ago
8 0

Answer:

Because  two minerals can share property's so you need more then one to tell them apart. Hope this helped! :)

Explanation:

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its answer is 35.5 grams

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3 years ago
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Which of the following statements correctly explains how latitude affects temperature?
dusya [7]

Answer:

It's 1, places that are closer to the equator receive more direct sunlight and have

Explanation:

7 0
2 years ago
PLEASE HELP ME ASAPP!!
aliina [53]

Conduction-

putting an icepack on injury

grabbing a warm coffee mug

burning yourself by touching boiling water

the handle of a pot being to hot to touch

Convection-

heat from a fire to warm hands

warm water rising to the surface of of the ocean etc.

warm air rising off pavement

an oven that cooks by cycling warm air through the bottom and out the top

Radiation-

cooking popcorn using microwave

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good luck on what your working on !!

7 0
3 years ago
Determine what’s wrong with these electronic configurations
Anika [276]

Answer:

Explanation:

19) it is 3d10 instead of 4d10

20) it is missing 3p6, and 4s2 before 3d5

21) Ra is not a noble gas

22) Cs is not a noble gas

7 0
2 years ago
Calculate the pH of a solution prepared by mixing: (Show your work for these calculations) pk of acetic acid is 4.75 a. two mole
kupik [55]

Answer:

Explanation:

To calculate pH you need to use Henderson-Hasselbalch formula:

pH = pka + log₁₀ \frac{[A^-]}{[HA]}

Where HA is the acid concentration and A⁻ is the conjugate base concentration.

The equilibrium of acetic acid is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺ pka: 4,75

Where <em>CH₃COOH </em>is the acid and <em>CH₃COO⁻ </em>is the conjugate base.

Thus, Henderson-Hasselbalch formula for acetic acid equilibrium is:

pH = 4,75 + log₁₀ \frac{[CH_{3}COO^-]}{[CH_{3}COOH]}

a) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[2 mol]}

<em>pH = 4,75</em>

<em></em>

b) The pH is:

pH = 4,75 + log₁₀ \frac{[2 mol]}{[1mol]}

<em>pH = 5,05</em>

<em></em>

I hope it helps!

7 0
3 years ago
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