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Fed [463]
3 years ago
7

If the total mechanical energy of the system is 100 J: Where does the pendulum have 100 J of kinetic energy? Where does the pend

ulum have 100 J of potential energy? (Label both points.)Where does the pendulum have 50 J of potential energy? (Label both
Physics
1 answer:
Katena32 [7]3 years ago
6 0

Answer:

See image and explanation

Explanation:

A simple pendulum consists of a string to which a bulb is attached and the string is tied to a support. The string swings from one end to the other as shown.

At the both ends, the energy of the pendulum is all potential. Hence we have 100J potential energy at both ends.

When the pendulum is in motion, the energy is all kinetic at the center of motion. Hence at that point, we have 100J kinetic energy.

In between both extremes the energy is both kinetic and potential as shown. The total energy is this a summation of the two.

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How does the law of conservation of energy apply to machines?
allsm [11]
Energy can be changed from one form to another, but it cannot be created or destroyed. ... This principle is referred to as the first law of thermodynamics or the law of energy conservation. The law applies to all systems both large and small, and, again, it states that energy cannot be created or destroyed.
4 0
3 years ago
Read 2 more answers
A meter stick is suspended vertically at a pivot point 22 cm from the top end. It is rotated on the pivot until it is horizontal
suter [353]

Answer:

5.82812 rad/s

Explanation:

L = Length of meter stick = 1 m = 100 cm

m_c = The center of mass of the stick = \frac{L}{2}-0.22=0.5-0.22=0.28\ m

\omega = Angular velocity

Moment of inertia of the system is given by

I=I_c+mr^2\\\Rightarrow I=\frac{mL^2}{12}+mr^2\\\Rightarrow I=\frac{m1^2}{12}+m0.28^2\\\Rightarrow I=m(\frac{1}{12}+0.0784)

As the energy in the system is conserved

mgh=I\frac{\omega^2}{2}\\\Rightarrow mgh=m(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow gh=(\frac{1}{12}+0.0784)\frac{\omega^2}{2}\\\Rightarrow \omega=\sqrt{\frac{2gh}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=\sqrt{\frac{2\times 9.81\times 0.28}{\frac{1}{12}+0.0784}}\\\Rightarrow \omega=5.82812\ rad/s

The maximum angular velocity is 5.82812 rad/s

4 0
3 years ago
WILL GIVE BRAINLIEST AND 30 POINTS!
mariarad [96]

Answer:

Gallium

Explanation:

Gallium is one such element used as a do/pant in a p-type semiconductor.

A do/pant is an impurity added to a semi-conductor used to alter its properties. Semi-conductors have a wide range of applications. They will conduct heat and electricity only under certain conditions. This property is highly desirable and find a wide application in electronics.

For p-type conductors, they are best do/ped with elements with 3 valence electrons. These are group 3 elements. From the choices, only gallium belongs to this group.

Other elements given are good do/pants for n-type semiconductors. They have 5 valence electrons.

8 0
3 years ago
If wheel turning at a constant rate completes 100 revolutions in 10 s its angular speed is:
GenaCL600 [577]
The frequency of the wheel is given by:
f= \frac{N}{t}
where N is the number of revolutions and t is the time taken. By using N=100 and t=10 s, we find the frequency of the wheel:
f= \frac{100}{10 s}=10 s^{-1}

And now we can find the angular speed of the wheel, which is related to the frequency by:
\omega=2 \pi f=2 \pi (10 s^{-1})=62.8 s^{-1}
6 0
3 years ago
Your high beam headlights illuminate the road in front of you for __________ feet. A. 150 B. 450 C. 650
ASHA 777 [7]

Answer:

B. 450 feet

Explanation:

Due to the angle at which high beam headlights illuminate, they can illuminate the road for about 450 feet.

8 0
3 years ago
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