Ask question

Ask question

All categories

3 years ago

10

A drag boat accelerates from rest to a velocity of 130.4 m/s in 11 seconds. What is the average acceleration of the boat during

this time?

1 answer:

Jet001 [13]3 years ago

6 0

Answer:

10. A boat traveling at 9.5 m/s reduces its acceleration at a rate of 2.5 m/s2. What is the final speed of the boat after it travels 12 meters?

You might be interested in

State the difference between sensible heat and latent heat

Anna11 [10]

<u>Latent hea</u>t is related to changes in phase between liquids ,gases and solids.

<u>Sensible heat</u> is related to changes in temperature of a gas or object with no change in phase.

6 0

3 years ago

To understand thermal linear expansion in solid materials. Most materials expand when their temperatures increase. Such thermal

Marat540 [252]

Answer:

Check the explanation

Explanation:

Kindly check the attached image below to see the step by step explanation to the question above.

5 0

3 years ago

Read the scenario below and answer the question that follows. Randall is hiring cooks for his restaurant. The first applicant is

Talja [164]

Randall has unconscious assumption that attractive people are more competent

4 0

3 years ago

A Carnot engine operates between temperature levels of 600 K and 300 K. It drives a Carnot refrigerator, which provides cooling

KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

$\frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$ ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

$\frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ ...... (2)

Now, equating both equations (1) and (2) as follows.

$Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}}$ = $Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}$

$\gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}$

= $\frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})$

= $\frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})$

= 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

4 0

3 years ago

Branches of sicence

Sonja [21]

Answer:

physical science

earth science and life science

5 0

3 years ago

Read 2 more answers