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algol [13]
3 years ago
12

3. How many atoms of hydrogen do 3.575 mol of hydrogen sulfide contain?

Chemistry
1 answer:
Ksju [112]3 years ago
4 0

Answer:

4.3043x10^24

Explanation:

Atoms(H) = (3.575 mol H2S/1)(2 mol H/1mol H2S)(6.02x10^23/1molH)

Simple stoicheometry problem. Sorry for taking so long, took Chem sophomore year, its been a while

You might be interested in
Name or write the formula for the following polyatomic ions
Delvig [45]

Answer:

Name                                Formula

nitrite ion                        NO2−

permanganate ion                MnO4−

phosphate ion                 PO43−

hydrogen phosphate ion      HPO42−

Explanation:

5 0
3 years ago
When heated, calcium hydroxide and ammonium chloride react to produce ammonia gas, water vapor, and solid calcium chloride.
NNADVOKAT [17]

Answer:

13.73g

Explanation:

mass of reactants = mass of products.

Mass reactants = 5.00 g + 10.00 g = 15.00 g

Mass products = 1.27g + mass of ammonia and water vapor

Mass of ammonia and water vapor

15.00g – 1.27 g = 13.73 g

3 0
3 years ago
Need Some Quick Help, Please :)
Ray Of Light [21]
I think that it is D because the higher the molecular mass, the higher it's boiling point. I hope that helped:) Bye!
6 0
3 years ago
Can you please help me and can you show your work please
natali 33 [55]

Answer:

1. 25 moles water.

2. 41.2 grams of sodium hydroxide.

3. 0.25 grams of sugar.

4. 340.6 grams of ammonia.

5. 4.5x10²³ molecules of sulfur dioxide.

Explanation:

Hello!

In this case, since the mole-mass-particles relationships are studied by considering the Avogadro's number for the formula units and the molar mass for the mass of one mole of substance, we proceed as shown below:

1. Here, we use the Avogadro's number to obtain the moles in the given molecules of water:

1.5x10^{25}molecules*\frac{1mol}{6.022x10^{23}molecules} =25 molH_2O

2. Here, since the molar mass of NaOH is 40.00 g/mol, we obtain:

1.2mol*\frac{40.00g}{1mol} =41.2g

3. Here, since the molar mass of C6H12O6 is 180.15 g/mol:

45g*\frac{1mol}{180.15g}=0.25g

4. Here, since the molar mass of ammonia is 17.03 g/mol:

20mol*\frac{17.03g}{1mol}=340.6g

5. Here, since the molar mass of SO2 is 64.06 g/mol:

48g*\frac{1mol}{64.06g} *\frac{6.022x10^{23}molecules}{1mol} =4.5x10^{23}molecules

Best regards!

5 0
3 years ago
Can someone help me please
almond37 [142]

Answer:D

Explanation:

  1. Use the vertex form, y=a(x−h)2+ky=a(x-h)2+k, to determine the values of aa, hh, and kk.a=14a=14h=6h=6k=1k=1Find the vertex (h,k)(h,k).(6,1)(6,1)Find pp, the distance from the vertex to the focus.
  2. Find the distance from the vertex to a focus of the parabola by using the following formula.14a14aSubstitute the value of aa into the formula.14⋅1414⋅14Simplify.
  3. Combine 4 and 1/4 .1 /4/4
  4. Simplify by dividing numbers
  5. Divide 4 by 44.1/1Divide 1 by 1/1.
  6. Y=0
  7. The Answer is D
5 0
2 years ago
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