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algol [13]
3 years ago
12

3. How many atoms of hydrogen do 3.575 mol of hydrogen sulfide contain?

Chemistry
1 answer:
Ksju [112]3 years ago
4 0

Answer:

4.3043x10^24

Explanation:

Atoms(H) = (3.575 mol H2S/1)(2 mol H/1mol H2S)(6.02x10^23/1molH)

Simple stoicheometry problem. Sorry for taking so long, took Chem sophomore year, its been a while

You might be interested in
Ions Types of Ions Cation Anion 1. H+ 2.O-2 3.Ba2+ 4.Br- 5.Hg2+ 6.Li+ 7.Ca2+ 8.F- 9.S-2 10.Fe3+
fiasKO [112]

Explanation:

The species with a positive charge over it, which means lack of electrons are called cations. Whereas the species with negative over it, meaning it has an excess of electrons with it are called anions.

From the list given the cations are

H+, Ba2+, Hg2+, Li+, Ca2+ and Fe2+

Whereas anions from the list are

O-2, Br-5, F-, S-2.

A Combination of cation and anions make an ionic compound in which cation is written first and then anion.

6 0
2 years ago
Consider this reaction mechanism: Step 1: Mo(CO)6→ Mo(CO)5 + CO Step 2: Mo(CO)5 + P(CH3)3→ Mo(CO)5P(CH3)3 Which of these is an i
Alja [10]

Answer:

Mo(CO)5 is the intermediate in this reaction mechanism.

Explanation:

The reaction mechanism describes the sequence of elementary reactions that must occur to go from reactants to products. Reaction intermediates are formed in one step and then consumed in a later step of the reaction mechanism.

In this reaction mechanism, Mo(CO)5 is the product of 1st reaction and then it is used as a reactant in 2nd reaction. So, Mo(CO)5 is the reaction intermediates.

The overall balanced equation would be,

Mo(CO)6 + P(CH3) ↔ CO + Mo(CO)5 +  P(CH3)3

4 0
2 years ago
How many bromine atoms are present in 39.4 g of CH2Br2
strojnjashka [21]
37.8 g CH2Br2 X (1 mol CH2Br2 / 173.83 g) = 4.60X10^-3 mol CH2Br2 

<span>4.60X10^-3 mol CH2Br2 X (2 mol Br / 1 mol CH2Br2) X 6.02X10^23 atoms/mol = 5.54X10^21 bromine atoms</span>
7 0
3 years ago
It takes 167 s for an unknown gas to effuse through a porous wall and 99 s for the same volume of n2 gas to effuse at the same t
irakobra [83]

Answer : The molar mass of the unknown gas will be 79.7 g/mol


Explanation : To solve this question we can use graham's law;


Now we can use nitrogen as the gas number 2, which travels faster than gas 1;

So, 167 / 99 = 1.687 So the nitrogen gas is 1.687 times faster that the unknown gas 1

We can compare the rates of both the gases;


So here, Rate of gas 2 / Rate of gas 1 = \sqrt{(molar mass 1 / molar mass 2)}

Now, 1.687 = square root [\sqrt{(molar mass 1) / (28.01 g/mol N_{2})} ]


When we square both the sides we get;


2.845 = (molar mass 1) / (28.01 g/mol N2)


On rearranging, we get,


2.845 X (28.01 g/mol N2) = Molar mass 1

So the molar mass of unknown gas will be = 79.7 g/mol

3 0
3 years ago
What characteristics are used to clarify an area as a wetland?
Nadya [2.5K]
Soil covered, saturated, submerged, flooded w water, standing water
5 0
3 years ago
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