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3 years ago

Will mark brainliest

Physics

1 answer:

Yuri [45]3 years ago

3 0

Answer:

v = u +at

Explanation:

The equation that relates the final velocity and the average acceleration is written as follows :

v = u +at

Where

v is final velocity

u is initial velocity

a is acceleration

t is time

This equation is valid when the motion is with constant acceleration.

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Which of the following statements are true for electric field lines? Check all that apply. Check all that apply. Electric field

Scilla [17]

Answer:

Electric field lines point away from positive charges and toward negative charges. True

Electric field lines are continuous; they do not have a beginning or an ending. False

Electric field lines can never intersect. True

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

Explanation:

Electric field lines point away from positive charges and toward negative charges. Always the field lines go to negative charges and leave from positive charges.

Electric field lines are continuous; they do not have a beginning or an ending. False

Because the field lines starts at positive charges and ends in negative charges.

Electric field lines can never intersect. True

It can not intercept the field lines because in that point the the field would have two directions. Besides, in that point the real value of the field should be found adding both field lines.

Electric field lines are close together in regions of space where the magnitude the electric field is weak and are father apart where it is strong. False

This fact is opposite to that so the regions of space where the magnitude the electric field is weak the lines are father apart and where the field is strong the lines are close together.

At every point in space, the electric field vector at that point is tangent to the electric field line through that point. True

This statement correspond to the definition of the field line.

5 0

3 years ago

Charge is uniformly distributed throughout a spherical insulating volume of radius R=4.00 cm . The charge per unit volume is −6.

aleksley [76]

Answer

-8.67× 10^6 N/C

Explanation:

The Electric Field is defined as force per unit charge.

E = Q/ 4π£r2

Qv= −6.5 μCm3

Qv = Q/ V= Q/ 4/3 πr3

Hence Q = 4/3 πr3 × Qv

Hence E = 4/3 πr3 × Qv / 4π£r2= Qvr/3£

−6.5 μ × 4/ 3×8.854 ×10^-12

-6.5 × 4 × 10^6/3 = -8.67× 10^6 N/C

Note: £ = 8.854×10^-12m/F

is the permittivity of free space

Qv is the charge per unit volume

V is volume and volume

8 0

3 years ago

I have 510 missing assignments on edg, Any tips on catching up?

RSB [31]

Answer:

Take notes

Explanation:

Cuz it helps you stay on task

6 0

3 years ago

Read 2 more answers

शब्द के जिस रुप से उसके पुरुष जाति के होने का बोध होता है उसे कहते हैं?

AVprozaik [17]

Answer:

Algebra For what values of the variables must ABCD be a parallelogram?

23. A 2y + 2 B 24. B

(3x + 10)

(8x + 5)º

3x + 6

54°

Зу - 9 с

ly+4

8 0

3 years ago

1. Consider a circular track with a radius of 200 meters. A runner starts on the east side and runs around the track to a point

ladessa [460]

Answer:

The magnitude of her displacement when at a point diametrically opposite her starting point is 400 meters

After she has returned to her starting point, the magnitude of her displacement is zero

Explanation:

Displacement is a vector quantity defined as the length of the shortest path between the final and the initial points. In other words, displacement can be defined as the distance traveled in a straight line.

From the question,

The circular track has a radius of 200 meters.

The runner starts on the east side to a point diametrically opposite her starting point. The diametrically opposite point is the point at the opposite end of the diameter of the circle.

Hence, her displacement ( that is, the length of the shortest path between her final and her initial points) is the length of the diameter of the circle.

Diameter d, of a circle is given as twice the radius r, of the circle.

That is, d = 2r

Radius r, of the circular track is 200 meters

∴ d = 2r = 2 (200 meters)

d = 400 meters

Hence, her displacement when at a point diametrically opposite her starting point is 400 meters

Now, after she has returned to her starting point, the magnitude of her displacement is zero.

This is because, the length between her final point ( which is the same as her initial point) and her initial point in zero.

7 0

3 years ago