Answer:
11060M Joules, where M is the mass of the diver in kg
Explanation:
Mass of the skydiver missing, we're assuming it's M.
It's total energy is the sum of the contribution of his kinetic energy (K)- since he's moving at 50 m/s, and it's potential energy (U), since he's subject to earth gravity.
Energy is the sum of the two, so
Answer:
a) 0.022%
b) 10014.32 lb
Explanation:
a) Percentage uncertainty would be
Percent uncertainty is 0.022%
b) For 1 kg uncertainty mass in kg would be
Mass in pounds would be
Mass in pound-mass is 10014.32 lb
The rate of fuel burning in grams per hour if the DT reaction is used is 1.08 × J/g per hour
<h3>How is the rate of fuel burning in grams per hour calculated when the D-T reaction is used?</h3>
E = 17.59 MeV
Mass = 2.014u + 3.016u
= 5.030u
Energy per Kg = (17.59××1.6×
) ÷ ( 5.030×1.66×
)
= 3.37× J/Kg
= 3.0× J/g
Rate of fuel burning in grams per hour = 3.0× × 3600
= 3.6×3.0×
= 1.08 × J/g per hour
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