Answer:
10m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 100m/s
Time taken = 10s
Unknown:
Acceleration = ?
Solution:
Acceleration is the rate of change of velocity with time.
A =
v = final velocity
u = initial velocity
t = time taken
So, insert the parameters and solve;
A =
= 10m/s²
The answer is c. velocity
Answer:
392 N
Explanation:
Draw a free body diagram of the rod. There are four forces acting on the rod:
At the wall, you have horizontal and vertical reaction forces, Rx and Ry.
At the other end of the rod (point X), you have the weight of the sign pointing down, mg.
Also at point X, you have the tension in the wire, T, pulling at an angle θ from the -x axis.
Sum of the moments at the wall:
∑τ = Iα
(T sin θ) L − (mg) L = 0
T sin θ − mg = 0
T = mg / sin θ
Given m = 20 kg and θ = 30.0°:
T = (20 kg) (9.8 m/s²) / (sin 30.0°)
T = 392 N
Answer:
<u>
</u> is the centripetal acceleration.
Explanation:
As per given values
Radius of earth (r) = 6371000 m
The "international space station" is orbiting with a velocity (v) = 7667 m/s.
"Centripetal acceleration" is the acceleration is equal to "the square of the velocity" divided by "the radius of the circular path".

V = velocity of the orbit
R = radius of the earth + height of the space station
R = 6,371,000 + 408,000
R = 6779000 m
The direction of the centripetal acceleration is always inwards along the radius vector of the circular motion.




i think the best answer for this question is B)