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Free_Kalibri [48]
3 years ago
15

A compound with the empirical formula CH 2 CH2 has a molar mass of 126 126 g/mol. What is the molecular formula for this compoun

d?
Chemistry
1 answer:
Pachacha [2.7K]3 years ago
6 0

<u>Answer:</u> The molecular formula of the compound is C_9H_{18}

<u>Explanation:</u>

We are given:

Empirical formula of the compound = CH_2

For determining the molecular formula, we need to determine the valency which is multiplied by each element to get the molecular formula.

The equation used to calculate the valency is :

n=\frac{\text{Molecular mass}}{\text{Empirical mass}}

We are given:

Mass of molecular formula = 126 g/mol

Mass of empirical formula = 12+(2\times 1)]=14g/mol

Putting values in above equation, we get:

n=\frac{126g/mol}{14g/mol}=9

Multiplying this valency by the subscript of every element of empirical formula, we get:

C_{(9\times 1)}H_{(9\times 2)}=C_9H_{18}

Hence, the molecular formula of the compound is C_9H_{18}

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