Answer:
B and E
Step-by-step explanation:
B = - 6, D = - 2, E = 2
d(B, D) = - 2-(-6)= - 2 + 6 = 4 units
d(D, E) 2 - (-2) = 2 + 2 = 4
Since, d( B, D) = d( D, E)
Therefore, Point D is 1/2 of the distance between B and E.
787-10=777
777/3=259
259 multiples of 3
<h3>
Answer: 8/25</h3>
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Explanation:
In a standard deck, there are 52 cards.
If this deck is missing the queen of hearts and 2 of clubs, then we really have 52-2 = 50 cards in the deck.
There are 4 aces and 13 spades. Those values add to 4+13 = 17, but we need to subtract off 1 to account for the ace of spades counted twice. We have 17-1 = 16 cards that are either an ace, a spade, or both.
Or you can think of it like saying 13 spades + 1 ace of hearts + 1 ace of diamonds + 1 ace of clubs = 16 cards total.
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The event space has A = 16 cards in it, while the sample space has B = 50 cards.
The probability we're after is A/B = 16/50 = 8/25
Answer:
its 300
Step-by-step explanation:
ik its is bc i got it right
