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3 years ago

10

Determine the magnitude of force P needed to start towing the 40kg crate.Also determine the location of the resultant normal for

ce acting on the crate

1 answer:

erastova [34]3 years ago

5 0

The distance from Point A=500 mm

Explanation:

M := 40kg c := 200mm

μs := 0.3 d := 3

a := 400mm e := 4

b := 800mm

Initial guesses: $N_{c}$ := 200 N P := 50N

Plz refer to the image below

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A cartridge electrical heater is shaped as a cylinder of length L=200mm and outer diameter D=20 mm. Under normal operating condi

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Answer:

T(water)=50.32℃

T(air)=3052.6℃

Explanation:

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To solve this problem we must use the equation that defines the transfer of heat by convection, which consists of the transport of heat through fluids in this case water and air.

The equation is as follows!

$Q=ha(Ts-T\alpha )$

Q = heat

h = heat transfer coefficient

Ts = surface temperature

T = fluid temperature

a = heat transfer area

The surface area of a cylinder is calculated as follows

$a=\pi D(\frac{D}{2} +L)$

Where

D=diameter=20mm=0.02m

L=leght=200mm)0.2m

solving

$a=\pi (0.02)(\frac{0.02}{2} +0.2)=0.01319m^2$

For water

Q=2Kw=2000W

h=5000W/m2K

a=0.01319m^2

Tα=20C

$Q=ha(Ts-T\alpha )$

solving for ts

$Ts=T\alpha +\frac{Q}{ha}$

$Ts=20+\frac{2000}{(0.01319)(5000)} =50.32C$

for air

Q=2Kw=2000W

h=50W/m2K

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A 0.25" diameter A36 steel rivet connects two 1" wide by .25" thick 6061-T6 Al strips in a single lap shear joint. The shear str

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Answer:

Option B

1025 psi

Explanation:

In a single shear, the shear area is $\frac {\pi d^{2}}{4}=\frac {\pi 0.25^{2}}{4}$

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3 years ago

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Explanation:

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3 years ago

Identify the different engineering activities/steps in the engineering design process for each steps,summarize in 1–3 sentences

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Answer:

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3 years ago

An alloy is evaluated for potential creep deformation in a short-term laboratory experiment. The creep rate is found to be 1% pe

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Answer:

a) Q = 251.758 kJ/mol

b) creep rate is $= 1.751 \times 10^{-5} \% per hr$

Explanation:

we know Arrhenius expression is given as

$\dot \epsilon =Ce^{\frac{-Q}{RT}$

where

Q is activation energy

C is pre- exponential constant

At 700 degree C creep rate is $\dot \epsilon = 5.5\times 10^{-2}$ % per hr

At 800 degree C creep rate is $\dot \epsilon = 1$ % per hr

activation energy for creep is $\frac{\epsilon_{800}}{\epsilon_{700}}$ = $= \frac{C\times e^{\frac{-Q}{R(800+273)}}}{C\times e^{\frac{-Q}{R(700+273)}}}$

$\frac{1\%}{5.5 \times 10^{-2}\%} = e^{[\frac{-Q}{R(800+273)}] -[\frac{-Q}{R(800+273)}]}$

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solving for Q we get

Q = 251.758 kJ/mol

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we know

$C = \epsilon e^{\frac{Q}{RT}}$

$=- 1\% e{\frac{251758}{8.314(500+273}} = 1.804 \times 10^{12} \% per hr$

$\epsilon_{500} = C e^{\frac{Q}{RT}}$

$= 1.804 \times 10^{12} e{\frac{251758}{8.314(500+273}}$

$= 1.751 \times 10^{-5} \% per hr$

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3 years ago