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podryga [215]
3 years ago
12

In a few sentences, describe the molecular polarity and the intermolecular forces present in ammonium lauryl sulfate.

Chemistry
1 answer:
Vladimir79 [104]3 years ago
8 0
The common name of ammonium dodecyl sulfate is ammonium lauryl sulfate (ALS) with molecular formula (CH3(CH2)10CH2OSO3NH4). ... Hence, one intermolecular force that is present in this molecule is electrostatic forces of attraction between the non-polar chain and polar end group.
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F2(g)+2Br(aq)=Br(t)+F(aq)<br> which species is redused?<br> a)F<br> b)Br<br> c)F2<br> d)Br2
ololo11 [35]

The Answer For Your Question is:

A) F

4 0
3 years ago
In the laboratory a student combines 47.8 mL of a 0.321 M aluminum nitrate solution with 21.8 mL of a 0.366 M aluminum iodide so
alex41 [277]

Answer: The final concentration of aluminum cation is 0.335 M.

Explanation:

Given: V_{1} = 47.8 mL (1 mL = 0.001 L) = 0.0478 L

M_{1} = 0.321 M,       V_{2} = 21.8 mL = 0.0218 L,      M_{2} = 0.366 M

As concentration of a substance is the moles of solute divided by volume of solution.

Hence, concentration of aluminum cation is calculated as follows.

[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}

Substitute the values into above formula as follows.

[Al^{3+}] = \frac{M_{1}V_{1} + M_{2}V_{2}}{V_{1} + V_{2}}\\= \frac{0.321 M \times 0.0478 L + 0.366 M \times 0.0218 L}{0.0478 L + 0.0218 L}\\= \frac{0.0153438 + 0.0079788}{0.0696}\\= 0.335 M

Thus, we can conclude that the final concentration of aluminum cation is 0.335 M.

4 0
3 years ago
Which of these are true for a hypothesis? (You can pick more than one)
Naya [18.7K]

Hypotheisis is just like an initial building block for a building. The true statements about hypothesis among the given are-

  • First guess- hypothesis is a proposed explanation for something which is observed. Thus the explanation is just a guess and not a proved one.
  • An initial idea which is assumed to be true - The whole experiment or research is based on an assumption which is supposed to be true and the scientist works to prove that true.
6 0
3 years ago
An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in
Advocard [28]
The correct answer for, An element with the smallest anionic (negative-ionic) radius would be found on the periodic table in, is <span>Group 17, Period 2.</span>
5 0
3 years ago
Using the fact that at 0.10 M, the absorbance was 0.357; and at 0.20 M, the absorbance was 0.714, the absorptivity (slope) is
olga_2 [115]

Answer:

The answer is "3.57 and 0.07".

Explanation:

Using the slop formula:

=\frac{n_2-n_1}{n_2-n_1}\\\\ =\frac{0.714-0.357}{0.20-0.10} \\\\ = ABSORPTIVITY, \ \ a=3.57 \\\\A= a\times b \times c

Given:

A=0.250

length path b=1  

from calibration it is found that

a=3.57\\\\consentation \ c=\frac{A}{a\times b} \\\\C=\frac{0.250}{3.57\times 1}

   =0.07 \ M

3 0
3 years ago
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