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3 years ago

When we add friction into the skate park what happens to the skater? Skate park questions

Chemistry

1 answer:

Sveta_85 [38]3 years ago

7 0

Answer:

If you put friction in to skating rink then obvioulsy the skaters wont be able to glide and skate.

Explanation:

friction is power that disturbes the moving power. places like skating rink and slides try to have the least amount of friction.

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What is a neutron and what charge does it have

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It’s a polyatomic and it has a negative charge. It’s located in the nucleus of the atom, along with the protons.

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3 years ago

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Due to the lower pressure on top of Mt. Everest, water can

Alla [95]

C. 343K
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3 years ago

State the basicity of this acid HCOOH

Katena32 [7]

Answer:

The basicity of HCOOH (otherwise known as formic acid) is 1

Explanation:

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3 years ago

Answer the following questions based on the reaction below: NaOH(aq) + KHP(s) --> NaKP(aq)+H2O(I)

Natali [406]

Answer:

a) 1.44g

b) 77.3%

Explanation:

1. Chemical balanced equation (given)

$NaOH(aq)+ KHP(s)\rightarrow NaKP(aq)+H_2O(l)$

2. Mole ratio

$1molNaOH(aq):1molKHP(s)$

This is, 1 mol of NaOH will reacts with 1 mol of KHP.

3. Find the number of moles in 72.14 mL of the base

$Molarity=\text{number of moles of solute}/\text{volume of solution in liters}$

$\text{Volume of solution}=72.14mL=0.07214liters$

$\text{Number of moles of NaOH}=0.0978M\times 0.07214liter=0.007055mol$

4. Find the number of grams of KHP that reacted

The number of moles of KHP that reacted is equal to the number of moles of NaOH, 0.007055 mol

Convert moles to grams:

mass = number moles × molar mass = 0.007055mol × 204.23g/mol

mass = 1.4408 g.

You have to round to 3 significant figures: 1.44 g (because the molarity is given with 3 significant figures).

5. Find the percentage of KHP in the sample

The percentage is how much of the substance is in 100 parts of the sample.

The formula is:

% = (mass of substance / mass of sample) × 100

% = (1.4408g/ 1.864g) × 100 = 77.3%

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3 years ago

35.0 mL of acid with an unknown concentration is titrated with 24.6 mL of 0.432 M base. What is the concentration of the acid? A

dusya [7]

Given:

35.0 mL of acid with an unknown concentration

24.6 mL of 0.432 M base

Required:

Concentration of the acid

Solution:

M1V1 = M2V2

M1 (35.0 mL of acid) = (0.432 M base) (24.6 mL of base)

V1 = (0.432 M base) (24.6 mL of base) / (35.0 mL of acid)

M1 = 0.304 M of acid

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3 years ago