Answer:
![[SO_2Cl_2]=0.0175M](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0175M)
Explanation:
Hello!
In this case, considering that the decomposition reaction of SO2Cl2 is first-order, we can write the rate law shown below:
![r=-k[SO_2Cl_2]](https://tex.z-dn.net/?f=r%3D-k%5BSO_2Cl_2%5D)
We also consider that the integrated rate law has been already reported as:
![[SO_2Cl_2]=[SO_2Cl_2]_0exp(-kt)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D%5BSO_2Cl_2%5D_0exp%28-kt%29)
Thus, by plugging in the initial concentration, rate constant and elapsed time we obtain:
![[SO_2Cl_2]=0.0225Mexp(-2.90x10^{-4}s^{-1}*865s)](https://tex.z-dn.net/?f=%5BSO_2Cl_2%5D%3D0.0225Mexp%28-2.90x10%5E%7B-4%7Ds%5E%7B-1%7D%2A865s%29)
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Answer:
MgBr2 < MgCl2 < NaBr < NaCl
Explanation:
In order to determinate ionic character, we have to subtract the electronegativity from the elements involved. This is known as Pauling rule.
MgBr2 > ΔΕΝ = 1.8
NaCl > ΔΕΝ = 2.3
MgCl2 > ΔΕΝ = 2
NaBr > ΔΕΝ = 2.1
Answer: Option C. p-dichlorobenzene and 1,4-dichlorobenzene.
Explanation:
A line-angle formula with six vertices and a circle inscribed corresponds to the compound known as benzene.
Further, according to the IUPAC standards for naming benzene derivatives, you must first number the position of the substituent. In this case, the substituents (chloros) are located at the positions 1 and 4; also, for the benzene derivatives when they have 2 substituents and the positions are 1 and 4, this configuration is known as <em>para </em>or <em>p </em>configuration.
Additionally, this compound has 2 substituents (chloros) so you have to indicate this number (di).
Therefore, the correct answer is C. p-dichlorobenzene and 1,4-dichlorobenzene.
It is false. The salt bridge is not a path for electrons, but a path for ions to flow from one half-cell to another. It help to balance the charge between the oxidation and reduction vessels.
