Answer:
Explanation:
q = 2e = 3.2 x 10^-19 C
mass, m = 6.68 x 10^-27 kg
Kinetic energy, K = 22 MeV
Current, i = 0.27 micro Ampere = 0.27 x 10^-6 A
(a) time, t = 2.8 s
Let N be the alpha particles strike the surface.
N x 2e = q
N x 3.2 x 10^-19 = i t
N x 3.2 x 10^-19 = 0.27 x 10^-6 x 2.8
N = 2.36 x 10^12
(b) Length, L = 16 cm = 0.16 m
Let N be the alpha particles
K = 0.5 x mv²
22 x 1.6 x 10^-13 = 0.5 x 6.68 x 10^-27 x v²
v² = 1.054 x 10^15
v = 3.25 x 10^7 m/s
So, N x 2e = i x t
N x 2e = i x L / v
N x 3.2 x 10^-19 = 2.7 x 10^-7 x 0.16 / (3.25 x 10^7)
N = 4153.85
(c) Us ethe conservation of energy
Kinetic energy = Potential energy
K = q x V
22 x 1.6 x 10^-13 = 2 x 1.5 x 10^-19 x V
V = 1.17 x 10^7 V
Answer:
Explanation:
<em>Position is the location of the object (whether it's a person, a ball, or a particle) at a given moment in time.</em>
<em>Displacement is the difference in the object's position from one time to another.</em>
<em>Distance is the total amount the object has traveled in a certain period of time.</em>
<em />
<em>I hope this helps!</em>
<em />
Answer:
20 m/s westward
Explanation:
Taking eastward as positive direction, we have:
is the velocity of Bill with respect to Amy (which is stationary)
is the velocity of Carlos with respect to Amy
Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

Therefore, Carlos velocity in Bill's reference frame will be

and the direction will be westward (negative sign).
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<em><u>A</u></em><em><u>L</u></em><em><u>S</u></em><em><u>O</u></em><em><u> </u></em><em><u>I</u></em><em><u>F</u></em><em><u> </u></em><em><u>Y</u></em><em><u>O</u></em><em><u>U</u></em><em><u> </u></em><em><u>D</u></em><em><u>O</u></em><em><u>N</u></em><em><u>T</u></em><em><u> </u></em><em><u>B</u></em><em><u>E</u></em><em><u>L</u></em><em><u>I</u></em><em><u>E</u></em><em><u>V</u></em><em><u>E</u></em><em><u> </u></em><em><u>S</u></em><em><u>E</u></em><em><u>A</u></em><em><u>R</u></em><em><u>C</u></em><em><u>H</u></em><em><u> </u></em><em><u>I</u></em><em><u>T</u></em><em><u> </u></em><em><u>F</u></em><em><u>R</u></em><em><u>O</u></em><em><u>M</u></em><em><u> </u></em><em><u>G</u></em><em><u>O</u></em><em><u>O</u></em><em><u>G</u></em><em><u>L</u></em><em><u>E</u></em>
Explanation:
Mass of the ball, m = 0.058 kg
Initial speed of the ball, u = 11 m/s
Final speed of the ball, v = -11 m/s (negative as it rebounds)
Time, t = 2.1 s
(a) Let F is the average force exerted on the wall. It is given by :


F = 0.607 N
(b) Area of wall, 
Let P is the average pressure on that area. It is given by :


P = 0.202 Pa
Hence, this is the required solution.