Question

The molar mass of HF is 20.01 g/mol. How many moles of Sn are required to react completely with 40 g of HF? 1 2 3 4

Answer 1

Answer:

1 mole of Sn is required to react with 40 gram of HF

Explanation:

It is given that molar mass of HF is 20.01 g/mol

Mass of HF is 40 gram

So number of of HF is

Number of moles $=\frac{mass\ in\ gram}{molar\ mass}$

$=\frac{40}{20.01}=1.9999=2moles$

When reaction between HF and Sn takes place

$Sn+2HF\rightarrow SnF_2+H_2$

From the reaction it is clear that 1 mole Sn require 2 moles HF

Therefore 2 moles of HF require 1 mole Sn