The final vertical velocity of the object is 705.6 m
Explanation:
Here we have to analyze the vertical motion of the object, which is a free fall motion, with constant acceleration of
![g=9.8 m/s^2](https://tex.z-dn.net/?f=g%3D9.8%20m%2Fs%5E2)
towards the ground due to gravity.
Therefore, we can use the following suvat equation:
![v=u+at](https://tex.z-dn.net/?f=v%3Du%2Bat)
where
v is the final vertical velocity
u is the initial vertical velocity
is the acceleration
t is the time
Since the object is dropped,
u = 0
Therefore, the magnitude of the vertical velocity of the object after t = 72 seconds is:
![v=0+(9.8)(72)=705.6 m/s](https://tex.z-dn.net/?f=v%3D0%2B%289.8%29%2872%29%3D705.6%20m%2Fs)
Learn more about free fall:
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