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Arte-miy333 [17]
3 years ago
15

What does the wavelength of visible light waves correspond to?

Physics
2 answers:
marissa [1.9K]3 years ago
7 0

Explanation:

Visible light is a very part of electromagnetic spectrum. We can see the visible region of the electromagnetic spectrum.

The frequency and the wavelength has an inverse relationship.

For example, the red light has large wavelength and low frequency. Violet has a short wavelength and higher frequency.

The frequency range of visible region is from 400 nm to 700 nm.

Lesechka [4]3 years ago
7 0

The wavelength of the visible range of the electromagnetic spectrum lies between \boxed{400\,{\text{nm}} - 700\,{\text{nm}}} .

Further Explanation:

The Electromagnetic spectrum is the complete range of the electromagnetic radiation which expresses all the radiation starting from the Gamma rays to the radio waves. The electromagnetic spectrum is the detailed spectrum that explains all the electromagnetic radiations.

The electromagnetic radiations are the transverse waves which do not require any medium for their propagation. The electromagnetic waves can easily travel through space. All the electromagnetic radiations travel at the speed of light.

The different radiations in the electromagnetic spectrum are as follows:

  • Gamma rays
  • X-rays
  • Ultraviolet rays
  • Infrared rays
  • Micro waves
  • Radio waves

The wavelength and the frequency ranges for the different electromagnetic radiations is as shown in figure attached.

Therefore, the wavelength of the visible range of the light in the electromagnetic spectrum is \boxed{400\,{\text{nm}} - 700\,{\text{nm}}} .

Learn More:

1. What is the threshold frequency ν0 of cesium <u>brainly.com/question/6953278 </u>

2. Calculate the wavelength of an electron (m = 9.11 × 10-28 g) moving at 3.66 × 106 m/s <u>brainly.com/question/1979815 </u>

3. What is the kinetic energy of the emitted electrons when cesium is exposed to UV rays <u>brainly.com/question/9059731 </u>

Answer Details:

Grade: High School

Subject: Physics

Chapter: Electromagnetic Waves

Keywords:

Electromagnetic spectrum, visible light, EM waves, wavelength, 700nm, 400 nm, 7000 A, frequency, gamma rays, transverse waves.

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KATRIN_1 [288]

Explanation:

Formula for maximum efficiency of a Carnot refrigerator is as follows.

      \frac{W}{Q_{H_{1}}} = \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}} ..... (1)

And, formula for maximum efficiency of Carnot refrigerator is as follows.

     \frac{W}{Q_{C_{2}}} = \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} ...... (2)

Now, equating both equations (1) and (2) as follows.

 Q_{C_{2}} \frac{T_{H_{2}} - T_{C_{2}}}{T_{C_{2}}} = Q_{H_{1}} \frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{1}}}        

        \gamma = \frac{Q_{C_{2}}}{Q_{H_{1}}}

                    = \frac{T_{C_{2}}}{T_{H_{1}}} (\frac{T_{H_{1}} - T_{C_{1}}}{T_{H_{2}} - T_{C_{2}}})

                    = \frac{250}{600} (\frac{(600 - 300)K}{300 K - 250 K})

                    = 2.5

Thus, we can conclude that the ratio of heat extracted by the refrigerator ("cooling load") to the heat delivered to the engine ("heating load") is 2.5.

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Why is it easier to change meters to centimeters than it is changing yards to feet?
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Which human body system provides nutrients for the body by breaking<br> down food? *
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A pharmacist attempts to weigh 100 milligrams of codeine sulfate on a balance with a sensitivity requirement of 4 milligrams. Ca
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Answer:

4 %

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Explanation:

Sensitivity requirement of 4 milligram means it is not sensitive below 4 milligram or can not measure below 4 milligram .

Given , 4 milligram is the maximum error possible .

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So percentage maximum potential error

= (4 / 100)  x 100

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Percentage of error =(.205 / 6 )x 100

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3 0
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RESOURCES: EOC V SLO
babunello [35]

Diffraction

Explanation:

The phenomenon through which a beam of light spreads out after leaving the flashlight and the beam grows wider and wider is known as diffraction.

Diffraction is one of the characteristics of waves. It implies the ability of waves to bend round an obstacle. The photons of light are able to bend round obstructions and continue to infinity in space.

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Learn more:

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