Answer:
5.4 × 10⁸ W/m²
Explanation:
Given that:
The Power (P) of Betelgeuse is estimated to release 3.846 × 10³¹ W
the mass of the exoplanet = 5.972 × 10²⁴ kg
radius of the earth = 1.27 × 10⁷ m
half the distance (i.e radius r ) = 7.5 × 10¹⁰ m
a) What is the intensity of Betelgeuse at the "earth’s" surface?
The Intensity of Betelgeuse can be determined by using the formula:


I = 544097698.8 W/m²
I = 5.4 × 10⁸ W/m²
Answer:
Not all of the time, it can also depend on the strength of the magnet.
Explanation:
say you have a small very strong magnet, that might work just as well as a large but week magnet.
The box is accelerated from rest to 4 m/s in a matter of 2.5 s, so its acceleration <em>a</em> is such that
4 m/s = <em>a</em> (2.5 s) → <em>a</em> = (4 m/s) / (2.5 s) = 1.6 m/s²
Then the force applied to the box has a magnitude <em>F</em> such that
<em>F</em> = (10 kg) (1.6 m/s²) = 16 N
Explanation:
Centripetal acceleration is the acceleration caused by centripetal force. It is equal to the square of the tangential velocity divided by the radius of the circular path.
a = v² / r
Yes, considering lava accommodates rocks that have collapsed of cave walls it is heterogeneous.