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3 years ago

WILL GIVE BRILLIANTIST

Physics

2 answers:

sleet_krkn [62]3 years ago

7 0

Answer: A. foliated

Explanation: took the test!

ser-zykov [4K]3 years ago

5 0

Answer:

C. NonFoliated

Explanation:

Non-foliated textures do not have lineations, foliations, or other alignments of mineral grains. Non-foliated metamorphic rocks are typically composed of just one mineral, and therefore, usually show the effects of metamorphism with recrystallization in which crystals grow together, but with no preferred direction.

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An 18 gauge copper wire (the size usually used for lamp cords), with a diameter of 1.02 mm,1.02 mm, carries a constant current o

larisa86 [58]

Answer:

J = 2.044x10⁶ A/m²

v = 1.50x10⁻⁴ m/s

Explanation:

The current density (J) of the copper wire is giving by:

$J = \frac {I}{A}$

where I: electric current and A: cross-sectional area of the copper wire

The cross-sectional area of the copper wire can be calculated by:

$A = \frac {\pi d^{2}}{4} = \frac {\pi (1.02 \cdot 10^{-3} m)^{2}}{4} = 8.17 \cdot 10^{-07} m^{2}$

Substituting the calculated area in the equation (1) we have:

$J = \frac {1.67 A}{8.17 \cdot 10^{-7} m^{2}} = 2.044 \cdot 10^{6} \frac {A}{m^{2}}$

Hence, the current density is 2.044x10⁶ A/m².

To find the drift speed (v), we need to use the next equation:

$v = \frac {J}{n q}$

where n: the free-electron density, q: module of the charge of the electron

$v = \frac {2.044 \cdot 10^{6} \frac {A}{m^{2}}}{(8.5 \cdot 10^{28} {m^{-3}}) (1.6 \cdot 10^{-19} C)}$

$v = 1.50 \cdot 10^{-04} \frac {m}{s}$

So, the drift speed is 1.50x10⁻⁴ m/s.

Have a nice day!

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What method of identifying substances is the best way to identify a chemical reaction

sertanlavr [38]

Chemical reaction produces new substances.
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3 years ago

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Shalnov [3]

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$\implies\cos\theta=\dfrac{14}{\sqrt{13}\sqrt{20}}$

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3 years ago

a student claims that since the model of the atom has been changed so many times, that means it is a weak model. State whether y

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KiRa [710]

Answer:

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Explanation:

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