Given:
Water, 2 kilograms
T1 = 20 degrees Celsius, T2 = 100
degrees Celsius.
Required:
Heat produced
Solution:
Q (heat) = nRT = nR(T2 = T1)
Q (heat) = 2 kilograms (4.184 kiloJoules
per kilogram Celsius) (100 degrees Celsius – 20 degrees Celsius)
<u>Q (heat) = 669.42 Joules
</u>This is the amount of heat
produced in boiling 2 kg of water.
Answer:
The value of the fund today is $13831.72
Explanation:
Let us calculate the value at the end of each year, step by step. An annual decrease of 3% corresponds to a multiplier 1.0-0.03 = 0.97. An increase of 7% corresponds to 1.07.
Value at the end of
year 1: 12000 * 0.97
year 2: 12000 * 0.97 * 0.97
year 3: 12000 * 0.97 * 0.97 * 1.07
year 4: 12000 * 0.97 * 0.97 * 1.07 * 1.07
year 5: 12000 * 0.97 * 0.97 * 1.07 * 1.07 * 1.07 = 13831.72
The value of the fund today (end of year 5) is $13831.72
Calculate the pressure due to sea water as density*depth.
That is,
pressure = (1025 kg/m^3)*((9400 m)*(9.8 m/s^2) = 94423000 Pa = 94423 kPa
Atmospheric pressure is 101.3 kPa
Total pressure is 94423 + 101.3 = 94524 kPa (approx)
The area of the window is π(0.44 m)^2 = 0.6082 m^2
The force on the window is
(94524 kPa)*(0.6082 m^2) = 57489.7 kN = 57.5 MN approx
Electric and magnetic field vectors are perpindicalar to each other in a electromagnetic wave. Passing stay current through a straight conductor shows some magnetic flux.
C= 5/9*(F - 32) so F=C*9/5 + 32
F= 25*9/5 +32 = 77 Fahrenheit
