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olga_2 [115]
3 years ago
10

When you walk on a floor, what pushes you along?

Physics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

In order to walk across the floor, you push backwards on the floor with your foot. Newton's Third Law says that the reaction force to this action force is "floor pushes you forward" (Action: You push floor (backwards). Reaction: floor pushes you (forward).) So, when you walk, it is the floor that pushes you along!

Explanation:

.

o-na [289]3 years ago
5 0
Your shoes
Answer friction
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A convex mirror of focal length 34 cm forms an image of a soda bottle at a distance of 18 cm behind the mirror. The height of th
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<h2>Answers:</h2>

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

<h2 /><h2>a) Position of the soda bottle (the object) </h2><h2 />

The Mirror equation is:

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}   (1)

Where:

f is the focal distance

u is the distance between the object and the mirror  

v is the distance between the image and the mirror

 

We already know the values of f and v, let's find u from (1):

u=\frac{v.f}{v-f}   (2)

Taking into account the explanation at the beginign of this asnswer:

f=-34cm and v=-18cm

The <u>negative signs</u> indicate the <u>focal distance</u> and the <u>distance between the image and the mirror are virtual </u>

Then:

u=\frac{(-18cm)(-34cm)}{-18cm-(-34cm)}  

u=38.25cm (3) >>>>Position of the soda bottle

<h2>b) magnification of the image </h2><h2 />

The magnification m of the image is given by:

m=-\frac{v}{u} (4)

m=-\frac{(-18cm)}{38.25cm}  

m=0.47 (5)>>>the image is 0.47 smaller than the object

<h2>The fact that this value is positive means the image is upright </h2>

<h2>c) Describe the image </h2><h2 />

According to the explanations and results obtained in the prior answers, the correct option is 9:

<h2>The image is <u>virtual, upright, smaller</u> than the object </h2><h2 /><h2>d) Height of the soda bottle (object) </h2>

Another way to find the magnification is by the following formula:

m=\frac{h_{i}}{h_{o}} (6)

Where:

h_{i} is the image height

h_{o} is the object height

We already know the values of m and h_{i}, let's find h_{o}:

h_{o}=\frac{h_{i}}{m} (7)

h_{o}=\frac{6.8cm}{0.47}  

h_{o}=14.46cm (8) >>>height of thesoda bottle

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