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2 years ago

A cup has a mass of 0.0650 kg and a

Physics

1 answer:

Roman55 [17]2 years ago

5 0

Answer: 0.185

Explanation:

Trust bro

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You are in the forest with some of your friends. You’re being chased by a very angry and hungry bear.

melomori [17]

Answer:

2m head start or else you done for

Explanation:

you cant even out run a bear they run at 35mph the fastest human is 25

8 0

2 years ago

A car company wants to ensure its newest model can stop in less than 450 ft when traveling at 60 mph. If we assume constant dece

seraphim [82]

Answer:

The value of acceleration that accomplishes this is 8.61 ft/s² .

Explanation:

Given;

maximum distance to be traveled by the car when the brake is applied, d = 450 ft

initial velocity of the car, u = 60 mph = (1.467 x 60) = 88.02 ft/s

final velocity of the car when it stops, v = 0

Apply the following kinematic equation to solve for the deceleration of the car.

v² = u² + 2as

0 = 88.02² + (2 x 450)a

-900a = 7747.5204

a = -7747.5204 / 900

a = -8.61 ft/s²

|a| = 8.61 ft/s²

Therefore, the value of acceleration that accomplishes this is 8.61 ft/s² .

4 0

2 years ago

How strong is the repulsive force exerted on two point charges that each carry 1.0 E-6 C of negative charge and are 0.30 meters

Brrunno [24]

Answer:

Match the scenario to the type of movement that caused it.

Ted is in his home when a strong vibration occurs that shakes the dishes out of his cupboards.

Whitney feels a slight tremor three weeks subsequent to an earthquake in a nearby town.

Sam pulls off the side of a road after feeling the road move unexpectedly while driving to work.

Foreshock

Mainshock

Aftershock

Explanation: PLZZ HELP ME I NEED TO PASS STEM!

6 0

2 years ago

Read 2 more answers

Why should the safety net that is used in circuses under trapezoids be little tightened?

bixtya [17]

So that there isn't too much force restricting the structure of the circus and cause disaster

8 0

2 years ago

A gymnast dismounts off the uneven bars in a tuck position with a radius of 0.3m (assume she is a solid sphere) and an angular v

kifflom [539]

Here we will say that there is no external torque on the system so we will have

$L_i = L_f$

here we know that

$L_i = I_1\omega_1$

where we know that

$I_1 = \frac{2}{5}mr^2$

Also we know that

$I_2 = \frac{1}{12}mL^2$

initial angular speed will be

$\omega_1 = 2\pi(2rev/s) = 4\pi rad/s$

now from above equation

$\frac{2}{5}mr^2 (4\pi) = \frac{1}{12}mL^2 \omega$

$0.4(0.3)^2(4\pi) = \frac{1}{12}(1.5)^2\omega$

$0.452 = 0.1875 \omega$

now we have

$\omega = 2.41 rad/s$

so final speed will be 2.41 rad/s

6 0

2 years ago