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wel
3 years ago
7

What is the correct order of the scientists in order of their work related to the structure of an atom from earliest to most rec

ent?
Neils Bohr, Ernest Rutherford, JJ Thomson, John Dalton, Democritus and Erwin Schrodinger
Erwin Schrodinger, JJ Thomson, John Dalton, Neils Bohr, Ernest Rutherford and Democritus
Democritus, John Dalton, JJ Thomson, Ernest Rutherford, Neils Bohr and Erwin Schrodinger
John Dalton, Neils Bohr, JJ Thomson, Democritus, and Ernest Rutherford and Erwin Schrodinger



PLEASE HELP !!!
Chemistry
1 answer:
Naddika [18.5K]3 years ago
4 0

Answer:

C. democritusm John dalton, JJ Thomason, Ernest Rutherford, Neils Bohr, and Erwin Schrodinger.

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Consider the cell described below at 259 K: Ni | Ni2+ (1.15 M) || Fe3+ (2.23 M) | Fe Given the standard reduction potentials fou
likoan [24]

Answer:

i dont know sorry :(

Explanation:

8 0
3 years ago
Calculate the volume of a 3.50 M solution of H2SO4 made from 49 g of H2SO4
maxonik [38]

Answer:

0.143L

Explanation:

Molar mass of H2SO4 = 98g/Mol

No of mole = mass/molar mass

No of mole= 49/98 = 0.5 mol

No of mol = concentration × volume

Volume = n/C = 0.5/3.5 = 0.143L

3 0
3 years ago
How many grams of water (H2O) are produced from 34 grams of oxygen (O2)? *
Dennis_Churaev [7]

Answer:

Explanation:

complete combustion reaction of  ethane is given by the reaction

2C2H6+7O2..............4CO2+6H2O

no of moles in 34 grams of O2=34/32=1.063

7mole of O2 produced 6 moles of H2O

therefore 1.063 moles of O2 produced=1.063*6/7=0.9 moles

now 0.9 moles of H2O contain how much grams=0.9*18=16.2 grams

3 0
3 years ago
A 7.12 L cylinder contains 1.21 mol of gas A and 4.94 mol of gas B, at a temperature of 28.1 °C. Calculate the partial pressure
GenaCL600 [577]

Answer:

P_A=4.20atm\\\\P_B=17.1atm

Explanation:

Hello!

In this case, since the equation for the ideal gas is:

PV=nRT

For each gas, given the total volume, temperature (28.1+273.15=301.25K) and moles, we can easily compute the partial pressure as shown below:

P_A=\frac{n_ART}{V} =\frac{1.21mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_A=4.20atm\\\\P_B=\frac{n_BRT}{V} =\frac{4.94mol*0.082\frac{atm*L}{mol*K}*301.25K}{7.12L} \\\\P_B=17.1atm

Best regards!

8 0
3 years ago
At S?fndnfnfnfxmckfkffkfkfk ckfkfkfkfkfkv kfflfmcmc
IRINA_888 [86]

Answer:

what?

Explanation:

3 0
3 years ago
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