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Ludmilka [50]
2 years ago
14

g The magnetic force on a charged particle A. depends on the sign of the charge on the particle. B. depends on the velocity of t

he particle. C. depends on the magnetic field at the particle's instantaneous position. D. is at right angles to both the velocity of the particle and the direction of the magnetic field. E. is described by all of these
Physics
2 answers:
Anni [7]2 years ago
7 0

Answer:

E. is described by all of these

Explanation:

Magnetic fields exert forces on a moving charged particle . The direction of the magnetic force on a moving charged particle is perpendicular to the plane formed by the velocity v and magnetic field B and follows right hand rule. The magnitude of the force is proportional to charge q, velocity v, and magnetic field strength B, and the sine of the angle between v and B.

Leona [35]2 years ago
3 0

Answer:

E) is described by all of these

Explanation:

The magnetic force on a charged particle is expressed as:

F = qv * B = qvBsinθ

Where,

q = charge on particle

θ = angle between the magnetic field and the particle velocity.

v = velocity of the particle

B = magnitude of field vector

From here, we could denote that magnetic force, F depends on charge on particle, velocity of particle, magnitude of field vector.

The magnetic force on a charged particle is at right angles to both the velocity of the particle. The magnetic force and magnetic field in a charged particle are perpendicular to each other, the right hand rule is used to determine the direction of force.

The correct option is E.

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a 2 kg laptop sits on the floor near a 4 kg jar of pennies. if the force of gravity between them is 3.42× 10⁻¹⁰ , how far apart
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The answer is 1.25 m

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You have been training and can run a mile in 6.5 minutes. How long would it take to run a lap around the outside track, which is
Paha777 [63]

Answer:

1 minute 36.85 seconds

Explanation:

First we need to convert the miles into meters, as the demanded result should be in meters.

1 mile = 1,609.34 meters

Also, 6.5 minutes should be converted into seconds.

1 minute = 60 seconds

6.5 x 60 = 390 seconds

Now we need to divide the miles with the seconds to see how much meters have been run in a second.

1,609.34 / 390 = 4.13 meters

The suggested meters now should be divided with the distance run in one second.

400 / 4.13 = 96.85 seconds

So we get a result of 96.85 seconds, or 1 minute 36.85 seconds.

5 0
2 years ago
An increase in the atomic number____the atomic radius moving from
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to

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7 0
3 years ago
A pipe is horizontal and carries oil that has a viscosity of 0.14 Pa s. The volume flow rate of the oil is 5.3 × 10-5 m3/s. The
Liula [17]

Answer:

Explanation:

Given

\mu =0.14 Pa.s

Volume Flow rate Q=5.3\times 10^{-5} m^3/s

Length L=37 m

radius r=0.58 cm

D=1.16 cm

According to Hagen-Poiseuille Equation

difference in Pressure is given

\Delta P=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}-P_{out}=\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=P_{out}+\frac{128\mu L\cdot Q}{\pi D^4}

P_{in}=1.01325\times 10^5+\frac{128\times 0.14\times 37\times 5.3\times 10^{-5}}{\pi\cdot 1.16^4\times 10^{-8}}

P_{in}=1.01325\times 10^5+6.17\times 10^5

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3 0
3 years ago
A 5.0 kg block hangs from the ceiling by a mass-less rope. A Second block with a mass of 10.0 kg is attached to the first block
gayaneshka [121]

The tension in the first and second rope are; 147 Newton and 98 Newton respectively.

Given the data in the question

  • Mass of first block; m_1 = 5.0kg
  • Mass of second block, m_2 =10kg
  • Tension on first rope; T_1 =\ ?
  • Tension on second rope; T_2 =\ ?

To find the Tension in each of the ropes, we make use of the equation from Newton's Second Laws of Motion:

F = m\ *\ a

Where F is the force, m is the mass of the object and a is the acceleration ( In this case the block is under gravity. Hence ''a" becomes acceleration due to gravity  g = 9.8m/s^2 )

For the First Rope

Total mass hanging on it; m_T = m_1 + m_2 = 5.0kg + 10.0kg = 15.0kg

So Tension of the rope;

F = m\ * \ g\\\\F = 15.0kg \ * 9.8m/s^2\\\\F = 147 kg.m/s^2\\\\F = 147N

Therefore, the tension in the first rope is 147 Newton

For the Second Rope

Since only the block of mass 10kg is hang from the second, the tension in the second rope will be;

F = m\ * \ g\\\\F = 10.0kg \ * 9.8m/s^2\\\\F = 98 kg.m/s^2\\\\F = 98N

Therefore, the tension in the second rope is 98 Newton

Learn More, brainly.com/question/18288215

4 0
2 years ago
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