Answer:
Lead to Sulfur = 2 : 1
Explanation:
Given
Represent lead with L and Sulfur with S
L1 = 6.46g for S1 = 1 g
L2= 3.23g for S2 = 1 g
Required
Determine the simple whole number ratio of L to S
Divide L1 by L2
L = L1/L2
L = 6.46g/3.23g
L = 2
Divide S1 by S2
S = 1g/1g
S = 1
Represent L and S as a ratio:
L : S = 2 : 1
Hence, the required ratio of Lead to Sulfur is 2 to 1
Answer:
Energy required to remove an electron from the atom.
Explanation:
Energy required to remove an electron from an atom describe ionization energy because in chemistry, ionization energy in is the amount of energy needed to remove electrons from the atoms or ions of chemical species.
Ionization energy increases as we move across the period of elements in the group and this is because electrons are bond tighter by high effective nuclear charge and ionization energy of elements increases down the group because electrons are bond together in lower energy orbitals.
They all have the same number of electrons in their outer shell.
Answer:
From the Online Catalog to the Shelf
Libraries in the United States generally use either the Library of Congress Classification System (LC) or the Dewey Decimal Classification System to organize their books. Most academic libraries use LC, and most public libraries and K-12 school libraries use Dewey.
Explanation:
This is an ideal gas problem. The gas inside the balloon is considered ideal. Ideal gas equation is a function pressure, temperature, amount and volume. Note: amount is constant since the balloon ins closed. Pressure is maintained constant since the walls are flexible. Ideal gas equation is: PV=nRT. Put all constant in one side and variables in one.
P/nR=T/V. To find the answer to the question equate the constants of both situation
T1/V1=T2/V2
(25+273.15)/3=(x+273.15)/2
x=-74.38 degC
