A. Solid
Solid structures are actually made of repeating patterns.
The grandfather clock will now run slow (Option A).
<h3>What is Time Period of an oscillation?</h3>
- The time period of an oscillation refers to the time taken by an object to complete one oscillation.
- It is the inverse of frequency of oscillation; denoted by "T".
Now,
, where L is the length and g is the gravitational constant, is the formula for a pendulum's period. - The period will increase as one climbs a very tall mountain because g will slightly decrease.
- Due to this and the previous issue, the clock runs slowly and it seems that one second is longer than it actually is.
Hence, the grandfather clock will now run slow (Option A).
To learn more about the time period of an oscillation, refer to the link: brainly.com/question/26449711
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Answer:
1) 3.9 %
2) 1,38 kg
3) 0.13 cubic meters
Explanation:
Part 1)
Calculated current = 0.180 amps
Measured current: 0.173 amps
percent error :
%
Part 2)
mass1 = 1,155 kg
mass2 = 0.22 kg
Addition; 1.155 + 0.22 = 1 375 kg which should be rounded to just two decimals according to the addition rules for uncertainties:
Answer : 1,38 kg
Part 3)
Volume = 0.885 x 0.20 x 0.75 cubic meters = 0.13275 cubic meters
Notice that the smallest number of significant figures among the set of dimension given is two. Therefore, our answer should be rounded to two significant figures. That is:
Volume = 0.13 cubic meters
Answer:
a) h = 593.50 m
b) h₁₁ = 103 m
c) vf = 107.91 m/s
Explanation:
a)
We will use second equation of motion to find the height:

where,
h = height = ?
vi = initial speed = 0 m/s
t = time taken = 11 s
g = 9.81 /s²
Therefore,

<u>h = 593.50 m</u>
b)
For the distance travelled in last second, we first need to find velocity at 10th second by using first equation of motion:

where,
vf = final velocity at tenth second = v₁₀ = ?
t = 10 s
vi = 0 m/s
Therefore,

Now, we use the 2nd equation of motion between 10 and 11 seconds to find the height covered during last second:

where,
h = height covered during last second = h₁₁ = ?
vi = v₁₀ = 98.1 m/s
t = 1 s
Therefore,

<u>h₁₁ = 103 m</u>
c)
Now, we use first equation of motion for complete motion:

where,
vf = final velocity at tenth second = ?
t = 11 s
vi = 0 m/s
Therefore,

<u>vf = 107.91 m/s</u>