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2 years ago

Water, oil and silver are poured into the vessel

Physics

1 answer:

taurus [48]2 years ago

7 0

The height of the oil column above the water in the vessel is determined as 2 cm.

<h3>Pressure of the vessel</h3>

The pressure of the vessel due to water, oil and silver poured into the vessel is determined from mercury column.

let level of mercury = 20 cm + 0.5 cm = 20.5 cm

20.5 cmHg = 205 mmHg

1 mmHg = 133.32 Pa

205 mmHg = 27,330.6 Pa

<h3>Height of the liquids in the vessel</h3>

P = ρgh

where;

ρ is the density of water, oil and silver respectively

ρ = 1000 kg/m³ + 881 kg/m³ + 10,800 kg/m³ = 12,681 kg/m³

h = P/(ρg)

h = (27,330.6) / (12,681 x 9.8)

h = 0.22 m

h = 22 cm

<h3>Height of oil column</h3>

Oil is less dense than water and will float on water.

Height of oil column = 22 cm - 20 cm = 2 cm

Learn more about density here: brainly.com/question/6838128

#SPJ1

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fomenos

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3 years ago

A body has masses of 0.013kg and 0.012kg in oil and water respectively, if the relative density of oil is 0.875, calculate the m

konstantin123 [22]

Answer:

the mass of the body is 0.02 kg.

Explanation:

Given;

relative density of the oil, $\gamma _0$ = 0.875

mass of the object in oil, $M_o$ = 0.013 kg

mass of the object in water, $M_w$ = 0.012 kg

let the mass of the object in air = $M_a$

weight of the oil, $W_0 = M_a - 0.013$

weight of the water, $W_w = M_a - 0.012$

The relative density of the oil is given as;

$\gamma_0 = \frac{density \ of \ oil }{density \ of \ water} = \frac{W_0}{W_w} = \frac{M_a -0.013}{M_a -0.012} \\\\0.875 = \frac{M_a -0.013}{M_a -0.012}\\\\0.875(M_a - 0.012) = M_a - 0.013\\\\0.875M_a - 0.0105 = M_a -0.013\\\\0.875M_a - M_a = 0.0105 - 0.013\\\\-0.125 M_a = -0.0025\\\\M_a = \frac{0.0025}{0.125} \\\\M_a = 0.02 \ kg$

Therefore, the mass of the body is 0.02 kg.

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3 years ago

HELP !!!!!

prohojiy [21]

Answer:D

Explanation:

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3 years ago

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All stars in a stellar cluster have roughly the same:___.

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All stars in a stellar cluster have roughly the same distance.

<h3>What coloration are celebrity clusters?</h3>

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<h3>Are stars in the identical cluster?</h3>

Though stellar associations are grouped in with megastar clusters, they're pretty a bit different. "Stellar associations are companies of tens to hundreds of stars that have similar a while and metallicities, and are moving in roughly the equal direction within the galaxy, but are no longer gravitationally bound," Geller said.

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1 year ago

Why does a hot-air balloon rise?

prohojiy [21]

Answer: The weight of the air displaced by the balloon is less than the volume of the balloon.

Explanation:

A hot air balloon is a cloth wrap that contains several thousand cubic meters of air inside (a large volume of air). The burner heats the liquid propane to a gaseous state to generate a huge flame, which can reach more than 3 meters, thus heating the air mass inside the balloon. In this way,<u> its density is modified with respect to the air that surrounds it</u>, because the hot air is lighter than the outside air (less dense), causing the balloon to rise and float.

Now, if we know that the density of a body $d$ is directly proportional to its mass $m$ and inversely proportional to its volume $V$ :

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We can deduce that <u>by increasing the volume of the body, its density will decrease.</u>

This is proof of <em><u>Archimedes' Principle</u></em>:

<em>A body totally or partially immersed in a fluid at rest, experiences a vertical upward thrust equal to the mass weight of the body volume that is displaced.</em>

In this case the fluid is the air outside. So, the warm air inside the balloon, being less dense, will weigh less than the outside air and therefore will receive an upward pushing force or thrust that will make the balloon ascend.

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3 years ago